Inequalities Involving Modulus Function
Trending Questions
Q. The value(s) of x satisfying the equation x9+98x6+2764x3−x+219512=0 is/are
- −1+√134
- −12
- −1−√134
- 12
Q.
If and are two events such that then
Q. The number of integral values of k for which ∣∣∣x2+kx+1x2+x+1∣∣∣<2 for all real values of x, is
Q. The solution set of x2−7x+12≥0 is
- [3, 4]
- (3, 4)
- (−∞, 3)∪(4, ∞)
- (−∞, 3]∪[4, ∞)
Q.
What is the prime factorization of ?
Q. If 1|x2−2|≤2, then x lies in the interval
- (−∞, −√52]∪[−√32, √32]∪[√52, ∞)
- (−∞, −√52]∪[√52, ∞)
- [−√32, √32]∪[√52, ∞)
- (−∞, −√52]∪(−√2, √2)
Q. Solution set of (x2−1)(x3−1)(x4−1)>0 is
- (−1, ∞)
- [1, ∞)
- [−1, ∞)
- (1, ∞)
Q. Number of integer values of x satisfying the inequality
|x−3|+|2x+4|+|x|≤11 is
|x−3|+|2x+4|+|x|≤11 is
Q. Let f(x) be a real-valued function such that ∣∣f(x)+x2+1∣∣≥|f(x)|+∣∣x2+1∣∣ and f(x)≤0 for all real values of x. Then the absolute value of 5∑r=1(1+f(r)) is
Q. The solution set of (x−1)99(x+1)100≤0 is
- (−∞, 1]
- (−1, 1)
- (1, ∞)
- (−∞, −1)
Q. The value of k for which the equation |x−2|+|x−6|−|x+1|=k has atleast one solution
- (1, ∞)
- (−∞, 3)
- [−3, ∞)
- (−∞, −1)
Q. The solution set of 16−x2≥0 is
- (−∞, −4]∪[4, ∞)
- [−4, 4]
- (−4, 4)
- (−16, 16)
Q. The solution set of x4−8x2−9≤0 is
- (0, 3)
- [−3, 3]
- (−3, 3)
- [3, ∞)
Q. The solution set of ∣∣∣3xx−3∣∣∣+|x|=x2|x−3| is
- (3, ∞)
- [3, ∞)
- {0}∪[3, ∞)
- {0}∪(3, ∞)
Q. Which of the following option represent the inequalities −3≤1−2x<7 and −5<4−3x4<7 on the number line?
- No Solution
Q. If −7≤x2+8x+5≤14, then the interval(s) in which x lies is/are
- (−8, −6)
- (−5, −2)
- (−1, 1)
- (1, 2)
Q. If |x+3|−|x−4|=4, then x=
- 4
- −3
- 7
- 52
Q. Complete values of a for which the equation |x−1|+|x−2|+x−a>0 has two solutions, is
- a ∈(−2, ∞)
- a ∈(2, ∞)
- a ∈(−∞, −2)
- a ∈(−5, ∞)
Q. The number of prime numbers in the solution set of |2x−9|+|2x−39|=30 is equal to
Q. If ∣∣∣1−|x|1+|x|∣∣∣≥12, then x∈
- [0, 1]
- [−1, 0]
- [−1, 1]
- R−[−1, 1]
Q. The number of solution(s) of the equation |x−|6−x||−2x=6 is
- 1
- 0
- 2
- infinite
Q. Solve |x+3|+xx+2>1
- (−5, −2)∪(−1, ∞)
- (−3, −2)∪(−1, ∞)
- (−5, −2)∪(1, ∞)
- (−5, −3)∪(−1, ∞)
Q.
Find the quotient and remainder and verify your answers:
Q. The solution set of ∣∣∣3xx−3∣∣∣+|x|=x2|x−3| is
- (3, ∞)
- [3, ∞)
- {0}∪(3, ∞)
- {0}∪[3, ∞)
Q.
If then
State whether the statement given is true (T) or false (F).
- True
- False
Q. The solution set of the inequality ||x|−1<1−x, 2∀xϵR is equal to
- (0, ∞)
- (−1, ∞)
- (−1, 1)
- (−∞, 0)
Q. The solution set of x2+4x+9≥0 is
- ϕ (empty set)
- R
- [−3, 4]
- [0, ∞)
Q. If |x|≥6, then x can be represented on the number line by
Q. If |4x−3|=|x+5|, then x is/are
- 83
- −25
- −83
- 25
Q. If |x|2−6|x|+9≤4, then x∈
- [−5, 5]−(−1, 1)
- [1, 5]
- [−5, 5]
- [−5, −1]