Inverse of a Function
Trending Questions
Q.
If is a relation from to defined by . Then, is equal to
None of these
Q. If f(x) is an invertible function and g(x)=2f(x)+5, then the value of g−1(x), is
- 2f−1(x)−5
- 12f−1(x)+5
- 12f−1(x)+5
- f−1(x−52)
Q. If f(x)=sinx+cosx, g(x)=x2−1 then g(f(x)) in invertible in the Domain
- [0, π2]
- [−π4, π4]
- [−π2, π2]
- [0, π]
Q. f:[a, ∞)→[a, ∞) is given by f(x)=x2−2ax+a(a+1), (a∈R). If one of the solutions of the equation f(x)=f−1(x) is 5049, then the other solution(s) may be
- 5050
- 5052
- 5048
- 5051
Q. If the equation cos−1(cosx)=n−xn, has seven roots for all x≥0, then n∈
- (0, 2π)
- (2π, 4π)
- (4π, 6π)
- (6π, 8π)
Q. Number of real solution of the equation x3+3x2−(x−6)13+8+3x=0 is
Q.
The relation R is defined on the set of natural numbers as {(a, b) : a = 2b}. Then R−1 is given by
{(2, 1), (4, 2), (6, 3).....}
{(1, 2), (2, 4), (3, 6)....}
R−1 is not defined
None of these
Q. Let A={1, 2, 3}, B={1, 3, 5}. A relation R is defined from A to B as R={(1, 3), (1, 5), (2, 1)}. Then R−1=
- {(1, 2), (3, 1), (1, 3), (1, 5)}
- {(1, 2), (3, 1), (2, 1)}
- {(1, 2), (5, 1), (3, 1)}
- {(1, 3), (1, 5), (2, 1)}.
Q. If f(x) is an invertible function and g(x)=2f(x)+5, then the value of g−1(x), is
- 2f−1(x)−5
- 12f−1(x)+5
- 12f−1(x)+5
- f−1(x−52)
Q. If p(x)=xn and q(x)=x1n, where n is odd, then p(x) and q(x) are inverse of each other.
- True
- False
Q.
The relation R is defined on the set of natural numbers as {(a, b) : a = 2b}. Then R−1 is given by
{(2, 1), (4, 2), (6, 3).....}
{(1, 2), (2, 4), (3, 6)....}
R−1 is not defined
None of these