Quadratic Formula for Finding Roots
Trending Questions
Q. The sum of all real values of x satisfying the equation (x2−5x+5)x2+4x−60=1 is :
- 6
- 3
- -4
- 5
Q.
The solution of is
Q. The number of the real roots of the equation (x+1)2+|x−5|=274 is
Q.
Using the quadratic formula solve for .
Q. The quadratic equation p(x) = 0 with real coefficients has purely imaginary roots. Then the equation p(p(x)) = 0 has
- one purely imaginary root
- all real roots
- two real and two purely imaginary roots
- neither real nor purely imaginary roots
Q. If x = √1+√1+√1+.....to infinity, then x =
- 1−√52
- 1+√52
- None of these
- 1±√52
Q. The value of √8+2√8+2√8+2√8+...∞ is
- 6
- −2 and 4
- 4
- 8
Q. The sum of the roots of the equation 3log√2x−12⋅3log2x+27=0 is
- 6
- 8
- 12
- 4
Q. If a∈R and the equation −3(x−[x])2+2(x−[x])+a2=0 (where, [x] denotes the greatest integer ≥x) has no integral solution, then all possible values of a lie in the interval
- (−1, 0)∪(0, 1)
- (-2, -1)
- (−∞, −2)∪(2, ∞)
- (1, 2)
Q. The set of values of a for which the function f(x)=ax33+(a+2)x2+(a−1)x+2 possesses a negative point of inflection is
- {−4, 5}
- (−∞, −2)∪(0, ∞)
- ϕ
- (−2, 0)
Q. The quadratic equation p(x) = 0 with real coefficients has purely imaginary roots. Then the equation p(p(x)) = 0 has
- one purely imaginary root
- all real roots
- two real and two purely imaginary roots
- neither real nor purely imaginary roots
Q. Let α and β be the roots of equation x2−6x−2=0 . If an=αnβn, for n≤1, then the value of a10−2a82a9 is equal to :
- 3
- -3
- 6
- -6
Q. if α, β are the roots of the equation x2−x+1=0, then α2009+β2009 =
- -1
- 1
- 2
- -2
Q. The sum of the roots of the equation 3log√2x−12⋅3log2x+27=0 is
- 4
- 6
- 8
- 12
Q. Let −π6<θ<−π12. Suppose α1 and β1 are the roots of the equation x2−2xsecθ+1=0 and α2 and β2 are the roots of the equation x2+2xtanθ−1=0. If α1>β1 and α2>β2, then α1+β2 equals:
- 2secθ
- −2tanθ
- 2(secθ−tanθ)
- 0
Q. The value of 2+12+12+.....∞ is
- 1−√2
- 1±√2
- √2
- None of these
Q. Let α and β be the roots of equation x2−6x−2=0 . If an=αnβn, for n≤1, then the value of a10−2a82a9 is equal to :
- 3
- -3
- 6
- -6
Q. If x = √1+√1+√1+.....to infinity, then x =
- 1+√52
- 1−√52
- 1±√52
- None of these
Q.
If ax2+bx+c=0, then x =
b±√b2−4ac2a
−b±√b2−ac2a
2c−b±√b2−4ac
None of these