Transitive Relations
Trending Questions
Q. Let R1 and R2 be two relations defined as follows:
R1={(a, b) ∈R2:a2+b2∈Q} and R2={(a, b) ∈R2:a2+b2∉Q}. Then
R1={(a, b) ∈R2:a2+b2∈Q} and R2={(a, b) ∈R2:a2+b2∉Q}. Then
- Neither R1 nor R2 is a transitive relation
- R1 and R2 both are transitive relations
- R1 is transitive but R2 is not a transitive relation
- R2 is transitive but R1 is not a transitive relation
Q. The relation R={(1, 1), (2, 2), (3, 3)} on the set {1, 2, 3} is
- Reflexive and Symmetric relation only
- Reflexive but not Transitive relation
- Equivalence relation
- Reflexive relation only
Q.
Let be a non-constant twice differentiable function defined on such that and, Then,
vanishes at least twice
Q. With reference to a universal set, the inclusion of a subset in another, is relation, which is
- Symmetric only
- Equivalence relation
- Reflexive only
- None of these
Q. Consider the following two binary relations on the set A={a, b, c}:
R1={(c, a), (b, b), (a, c), (c, c), (b, c), (a, a)} and R2={(a, b), (b, a), (c, c), (c, a), (a, a), (b, b), (a, c)}.
Then :
R1={(c, a), (b, b), (a, c), (c, c), (b, c), (a, a)} and R2={(a, b), (b, a), (c, c), (c, a), (a, a), (b, b), (a, c)}.
Then :
- R2 is symmetric but it is not transitive.
- both R1 and R2 are transitive.
- both R1 and R2 are not symmetric.
- R1 is not symmetric but it is transitive.
Q. A relation R is defined as aRb if “a is the father of b”. Then R is
- reflexive
- symmetric
- transitive
- none of these
Q. Let A={1, 2, 3} and R, S be two relations on A given by R={(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)}, S={(1, 1), (2, 2), (3, 3), (2, 3), (3, 2)} then R∪S is
- Reflexive, symmetric and transitive relation
- reflexive and transitive relation only
- not a transitive relation
- Reflexive relation but not Symmetric relation
Q.
Let R and S be two non-void relations on a set A. Which of the following statements is false
R and S are transitive then R ∪ S is not transitive
R and S are transitive then R ∩ S is transitive
R and S are symmetric then R ∪ S is symmetric
R and S are reflexive then R ∪ S is reflexive
Q. Let R be the relation on the set R of all real numbers defined by aRb iff |a−b|≤1. Then R is
- Reflexive and symmetric
- Symmetric only
- Transitive only
- Anti-symmetric only
Q. Consider the set A={1, 2, 3} and the relation on A as R={(1, 2), (1, 3)}, then R is
- a reflexive relation
- a symmetric relation
- a transitive relation
- None of the above
Q. Let R be a relation defined on N as R={(x, y):x, y∈N, 2x+y=41}. Then R is
- a symmetric relation
- both symmetric and transitive relation
- Neither reflexive nor symmetric nor transitive relation
- Symmetric relation but not transitive relation
Q.
Let R be a relation on the set N be defined by {(x, y)|x, y|N, 2x+y=41}. Then R is
Reflexive
Symmetric
Transitive
None of these
Q. Which of the following is not correct for relation R on the set of real numbers?
- (x, y)∈R⇔|x|–|y|≤1 is reflexive but not symmetric
- (x, y)∈R⇔0<|x|–|y|≤1 is neither transitive nor symmetric
- (x, y)∈R⇔0<|x–y|≤1 is symmetric and transitive
- (x, y)∈R⇔|x–y|≤1 is reflexive and symmetric
Q.
Which of the following relations are transitive?
"Shares birthday with" on set of people
"Is friends on Facebook with" on set of people in fb
"Is greater than" on a set of numbers
"Is elder to" on a set of people