Transpose Conjugate
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Given 2A∗+B∗=[−2i−4i−6i−8i] and all the elements of B are 2. Then matrix A is given by. (∗ represents transpose conjugate operator)
[i2i3i4i]
[−1+i−1+2i−1+3i−1+4i]
[2+2i2+4i2+6i2+8i]
[i−13i−12i−14i−1]
- XY
- YX
- – YX
- None of these
What is the transpose conjugate for the matrix. [2+3i−i55−i]
[2−3i−5−i5+i]
[−2−3i−5i−5+i]
[5−i−i52+3i]
[2−3i5i5+i]
- [−n110]
- [1−n01]
- [011−n]
- [10−n1]
Given 2A∗+B∗=[−2i−4i−6i−8i] and all the elements of B are 2. Then matrix A is given by. (∗ represents transpose conjugate operator)
[i2i3i4i]
[−1+i−1+2i−1+3i−1+4i]
[2+2i2+4i2+6i2+8i]
[i−13i−12i−14i−1]
If A and B are 2 matrices given by general elements aij and bij respectively. And bij = Im(aij). Then which the following are correct if A* + B = 0. ( Im(x) means Imaginary part of the number x)
A is a symmetric matrix
A is a non symmetric matrix
Sum of real parts of elements of A is zero
Sum of imaginary parts of elements of A is zero
If
Find ?