Analysis of Force Equation
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A uniform magentic field exists in space. A particle of mass m and charges q is projected towards negative x-axis with speed v from a point (d, 0, 0). The maximum value of v for which the particle does not hit the y-z plane is
2Bq/dm
Bqd/m
Bq/2dm
Bqd/2m
- Both the ions will be deflected equally
- He+ions will be deflected more than O2+ ions.
- He+ions will be deflected less than O2+ ions
- No ions will be deflected
['E' is parallel to 'B'.]
- Path of the charged particle may be straight line.
- Path of the charged particle is helix with increasing pitch.
- Frequency of the charged particle increases.
- Speed increases to thrice of its original speed in time 2√2V0mqE.
(V0 is initial speed)
- Electron
- Proton
- He+
- Li++
What is the source of magnetism in materials?
- No ions will be deflected
- Both the ions will be deflected equally
- He+ions will be deflected less than O2+ ions
- He+ions will be deflected more than O2+ ions.
- Positive ions deflect towards +y direction and negative ions towards – y direction
- All ions deflect towards + y direction
- All ions deflect towards – y direction
- Positive ions deflect towards – y direction and negative ions towards + y direction.
- 12
- 14
- 2
- 4
A square metal wire loop of side 10 cm and resistance 1 Ω is moved with a constant velocity v in a uniform magnetic field B = 2 T, as shown in Fig. 25.4. The loop is connected to 4 Ω resistor.
What should be the speed v of the loop as to have a steady current of 1 mA in the loop ?
1 cms−1
2 cms−1
3 cms−1
4 cms−1
- √qλ2ϵ0m
- √2qλϵ0m
- √qλϵ0m
- √3qλ2ϵ0m
- 14
- 2
- 3.5
- 28
- Electron
- Proton
- He+
- Li++
- 14
- 2
- 3.5
- 28
['E' is parallel to 'B'.]
- Path of the charged particle may be straight line.
- Path of the charged particle is helix with increasing pitch.
- Frequency of the charged particle increases.
- Speed increases to thrice of its original speed in time 2√2V0mqE.
(V0 is initial speed)
A uniform magentic field exists in space. A particle of mass m and charges q is projected towards negative x-axis with speed v from a point (d, 0, 0). The maximum value of v for which the particle does not hit the y-z plane is
2Bq/dm
Bqd/m
Bq/2dm
Bqd/2m
- 20 μF
- 10 μF
- 5 μF
- 40 μF
- 12
- 14
- 2
- 4
- Will go undeviated
- Will be deviated by the same angle and will not separate.
- Will be deviated by different angles and hence separate.
- Will be deviated by the same angle and separate.
- 10×10−12N
- 8×10−12N
- 2.5×10−10N
- 8×10−11N
- 5×10−11N along ^i
- 5×103 N along ^k
- 5×10−11N along ^j
- 5×10−4N along− ^k
Following the situation of the previous question, the magnitude of force required to move the conducting rod at a constant speed of 5 cms−1 at the same instant t=2s is equal to
- 0.16 N
- 0.12 N
- 0.08 N
- 0.06 N
- Gains Energy
- Loses Energy
- Moves along a circular path
- Moves along parabolic path
- Charge particle will never reach ground if H>2m2g(qB)2
- Vertical motion of charge particle will be SHM.
- Maximum speed attained by particle is 2mqB√g
- Motion of particle is oscillatory
- v<E/B
- v>E/B
- v=E/B
- None of these
- zero
- 2Brv
- 6Brv
- 10Brv