Centripetal Acceleration
Trending Questions
If the earth stops rotating, the apparent value of g on its surface will
Increase everywhere
Decrease everywhere
Remain the same everywhere
Increase at some places and remain the same at some other places
What causes circular motion?
- mvr
- mv2r
- vr2m
- vrm
A stone is tied to one end of a string 50 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 10 revolutions in 20 s, what is the magnitude of acceleration of the stone
493cm/s2
720cm/s2
720cm/s2
990cm/s2
A ball of mass 0.1 Kg. is whirled in a horizontal circle of radius 1 m. by means of a string at an initial speed of 10 R.P.M. Keeping the radius constant, the tension in the string is reduced to one quarter of its initial value. The new speed is
5 r.p.m.
10 r.p.m.
20 r.p.m.
14 r.p.m.
If the overbridge is concave instead of being convex, the thrust on the road at the lowest position will be
mg+mv2r
mg−mv2r
m2v2gr
v2gr
- (R2R1)2
- R1R2
- (R1R2)2
- √R1R2
If a particle is performing uniform circular motion with radius R, with angular velocity ⍵, then the magnitude of the acceleration is _____
- 1 km/s2
- 100 m/s2
- 10 m/s2
- 1 m/s2
- 6 m/s
- 14 m/s
- 18 m/s
- 12 m/s
(Take g=10 m/s2)
- At the top of the circle
- At the bottom of the circle
- Half way down
- None of above
A body is revolving with a constant speed along a circle. If its direction of motion is reversed but the speed remains the same, then which of the following statement is true
The centripetal force will not suffer any change in magnitude
The centripetal force will have its direction reversed
The centripetal force will not suffer any change in direction
The centripetal force would be doubled
- Centripetal force is doubled
- Centripetal force is halved
- Centripetal force remains same
- None of the above
- 1.75 m/s2
- 6.6 m/s2
- 1.3 m/s2
- 2.6 m/s2
- 1:3
- 3:1
- √3:2
- 1:√3
- 6.2 m/s
- 4.5 m/s
- 5.0 m/s
- 5.7 m/s
- 180 m/s2
- 320 m/s2
- 980 m/s2
- 500 m/s2
- 13mω2R
- 43mω2R
- 23mω2R
- mω2R
- Path of projectile after 0.6 sec is parabolic
- Path of ball after 0.6 sec will be circular and radius of circle will be 1.8 m
- Magnitude of the constant force applied is 32 N
- Speed during circular motion will be 8 m/s
- √rg
- √2rg
- √gh
- √2gh
- tan−1(110)
- tan−1(35)
- tan−1(1)
- tan−1(15)
- rg
- √rg
- rg
- gr
- False
- True
A body of mass 1 kg tied to one end of string is revolved in a horizontal circle of radius 0.1 m with a speed of 3 revolution/sec, assuming the effect of gravity is negligible, then linear velocity, acceleration and tension in the string will be
1.88 m/s, 35.5 m/s2, 35.5 N
2.88 m/s, 45.5 m/s2, 45.5 N
3.88 m/s, 55.5 m/s2, 55.5 N
None of these
- ln(1+RcosθL)ω
- ln(1+LcosθR)ω√sinθ
- ln(1+LcosθR)ω√cosθ
- ln(1+RcosθL)ω√cosθ
- 1:2
- 2:1
- 1:√2
- √3:1
- 3750 N
- 4485 N
- 3000 N
- 5843 N
If a cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be
π2m/s2
2π2m/s2
4π2m/s2
8πm/s2
A mass of 2 kg is whirled in a horizontal circle by means of a string at an initial speed of 5 revolutions per minute. Keeping the radius constant the tension in the string is doubled. The new speed is nearly
14 rpm
10 rpm
2.25 rpm
7 rpm
The speed of the particle as a function of the distance covered s will be
- v=v0e−sR
- v=v0esR
- v=v0e−R/s
- v=v0eR/s