Conduction Law: Differential Form
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Q. A metallic spherical shell having inner and outer radii a and b respectively has thermal conductivity K=K0r2{a≤r≤b}, where r is the distance from the center of the sphere. The inner surface is maintained at temperature θ1 and outer surface is maintained at temperature θ2 . Calculate the rate at which heat flows radially through the material [θ2>θ1].
- 4πK0(θ1−θ2)b−a
- 4πK0(θ2−θ1)b−a
- 4πK0(b−a)θ2−θ1
- 8πK0(θ2−θ1)b−a
Q.
Two materials A and B of different materials are welded together. Both the materials are having the same cross-sectional area and the same length. Their thermal conductivities are and . What is the thermal conductivity of the composite material?
Q.
Two different metal rods of the same length have their ends kept at the same temperatures θ1 and θ2 with θ2 > θ1. If A1 and A2 are their cross-sectional areas and k1 and k2 their thermal conductivities, the rate of heat flow in the two rods will be same if
k1k2=A1A2
k1k2=A2A1
k1k2=A1θ2A2θ1
k1k2=A1θ1A2θ2
Q. A metallic spherical shell having inner and outer radii a and b respectively has thermal conductivity K=K0r2{a≤r≤b}, where r is the distance from the center of the sphere. The inner surface is maintained at temperature θ1 and outer surface is maintained at temperature θ2 . Calculate the rate at which heat flows radially through the material [θ2>θ1].
- 4πK0(θ1−θ2)b−a
- 4πK0(θ2−θ1)b−a
- 4πK0(b−a)θ2−θ1
- 8πK0(θ2−θ1)b−a
Q. Two rods of same length but made of different material are taken for a study as shown in the figure. Area of cross-section of rod 1 is 12 cm2 and that of rod 2 is 16 cm2. Thermal conductivity of rod 1 is 0.0008 cal/cm-s-∘C. If rate of loss of heat due to conduction is equal, find the thermal conductivity of rod 2.
- 0.0006 cal/cm-s-∘C
- 0.0008 cal/cm-s-∘C
- 0.0010 cal/cm-s-∘C
- 0.0004 cal/cm-s-∘C
Q. A refrigerator door is 150 cm high, 80 cm wide and 6 cm thick. If the coefficient of conductivity is 0.0005 cal/cm-s-∘C and the inner and outer surfaces are at 0∘C and 30∘C respectively, find the heat loss per minute through the door. (in Calories)
- 3600
- 1800
- 900
- 1200