Conservation of Momentum
Trending Questions
[Given : The two planets are fixed in their position]
- Daughter nucleus is 20682Pb
- Disintegration energy of α - decay is 5.30 MeV
- Disintegration energy of α - decay is 5.40 MeV
- Mass of daughter nucleus is 205.9745 u
- 5vRcosθ
- 5v2Rcosθ
- 4vRcosθ
- 5vRsinθ
- mv23
- mv2
- mv26
- none of the above
Directions: Some questions (Assertion – reason type) are given below. Each question contains Statement I (Assertion) and statement II (Reason). Each question has 4 choices (a), (b), (c) and (d) out of which only one is correct. So, select the correct choice.
Statement I A single particle is having non- zero kinetic energy then its momentum can be zero.
Statement II Kinetic energy is a scalar quantity and is always positive, while momentum is a vector quantity.
Statement I is true, statement II is true, statement II is a correct explanation for statement I
Statement I is true, statement II is true, statement II is not a correct explanation for statement I
Statement I is true, statement II is false
Statement I is false, statement II is true
- 12 m/s
- 10 m/s
- 8 m/s
- 11 m/s
- 60 m/s
- 80 m/s
- 40 m/s
- 20 m/s
- 96 N
- 48 N
- 24 N
- 12 N
- √2gh
- 2ngh
- √2gh(1+1n)
- √2gh(1−1n)
- Daughter nucleus is 20682Pb
- Disintegration energy of α - decay is 5.30 MeV
- Disintegration energy of α - decay is 5.40 MeV
- Mass of daughter nucleus is 205.9745 u
(Assume that the small block does not leave surface of M and all surfaces are smooth)
- the block M will start moving due to force exerted by m
- the block M stays at rest as surface is smooth
- block M and m always move with same speed
- block M and m can never move with same speed
[Given : The two planets are fixed in their position]
- All the three pieces share the energy of blast equally
- The speed of bigger mass is √2 times the speed of either of the smaller mass
- The direction of motion of bigger mass makes an angle of 135∘ with the direction of smaller pieces
- The bigger piece carries double the energy of either piece.
- mv23
- mv2
- mv26
- none of the above
- 3v m/s
- v m/s
- 2v m/s
- None of these
A missile of mass 1 kg is moving with speed 10 m/s along the +ve x direction. Its target is a car weighing 100 kg, moving with 1 m/s also in the +ve x direction. The missile hits the target but doesn't burst. Find the combined velocity of car-missile system?
1 m/s
10 m/s
110101m/s
101110 m/s
- √ga14
- √ga21
- √ga10
- √ga36
A wagon weighing 1000 kg is moving with a velocity 50 km/h on smooth horizontal rails. A mass of 250 kg is dropped into it. The velocity with which it moves now is
12.5 km/hour
20 km/hour
40 km/hour
50 km/hour
(Assume that the small block does not leave surface of M and all surfaces are smooth)
- the block M will start moving due to force exerted by m
- the block M stays at rest as surface is smooth
- block M and m always move with same speed
- block M and m can never move with same speed
STATEMENT B- Kinetic energy of system of particles is zero.
- A does not imply B and B does not imply A.
- A implies B but B does not imply A
- A does not imply B but B implies A
- A implies B and B implies A.
- 0.20 ms−1
- 0.5 ms−1
- 0.67 ms−1
- 0.85 ms−1
- 1
- 2√3
- √32
- 12
- 40 N
- 45 N
- 54 N
- 60 N
- 12 m/s
- 10 m/s
- 8 m/s
- 11 m/s
- −12.5 m/s
- −1.25 m/s
- 12.5 m/s
- 1.25 m/s
- 6 m/s
- 8 m/s
- 9 m/s
- 12 m/s
- 40 N
- 45 N
- 54 N
- 60 N
- √ga14
- √ga21
- √ga10
- √ga36
- 192m J
- 96m J
- 384m J
- 768m J
- (23^i+43^j+83^k) m/s
- −(23^i+43^j+83^k) m/s
- (23^i−43^j+83^k) m/s
- (23^i−43^j−83^k) m/s