Constrained Motion : Intuitive Approach
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Find velocity of ring B (VB) at an instant as shown. The string is taut and inextensible:
12m/s
√34m/s
14m/s
1 m/s
A block of mass 2 kg slides down the face of a smooth 45∘ wedge of mass 9kg as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge.
2 m/s2.
11√2 m/s2.
1 m/s2.
none of these
- 212 m/s (upwards)
- 312 m/s (downwards)
- 312 m/s (upwards)
- 212 m/s (downwards)
- 3611 m/s2
- 4011 m/s2
- 367 m/s2
- 407 m/s2
- Velocity of pulley P1 will be 5 m/s downwards.
- Velocity of block C will be 25 m/s upwards.
- Velocity of pulley P1 will be 5 m/s upwards.
- Velocity of block C will be 15 m/s downwards.
In each of the three arrangements, the block of mass m1 is being pulled left with constant velocity. All surfaces are smooth. The strings are light and inextensible and pulleys are massless. The ratio of the speed of the block of mass m2 in the three cases respectively is:
2 : 1 : 4
2 : 4 : 1
4 : 2 : 1
can not be calculated
- Acceleration of block b is 0.5 m/s2
- Acceleration of block b is 1 m/s2
- Tension in the string is 10 N
- Acceleration of block c is 0.5 m/s2
- Acceleration of block b is 0.5 m/s2
- Acceleration of block b is 1 m/s2
- Tension in the string is 10 N
- Acceleration of block c is 0.5 m/s2
A block of mass 2 kg slides down the face of a smooth 45∘ wedge of mass 9kg as shown in figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge.
2 m/s2.
11√2 m/s2.
1 m/s2.
none of these
- a1=3a2
- 2a1=a2
- a1=2a2
- 3a1=a2
(Given that 'B' is constrained to move along vertical)
- 12 m/s
- 13 m/s
- 34 m/s
- 38 m/s
- 212 m/s (upwards)
- 312 m/s (downwards)
- 312 m/s (upwards)
- 212 m/s (downwards)
- 5.625 m
- 1.75 m
- 7.375 m
- 6.5 m
- 5mgk
- 3mgk
- 10mgk
- 4mgk
- U2
- 2U
- 2U√3
- √3U2