# Different Kinds of Motion

## Trending Questions

**Q.**

What is the difference between momentum and impulse?

**Q.**A truck starts from rest with an acceleration of 1.5 m/s2 while a car 150 m behind starts from rest with an acceleration of 2 m/s2. What is the distance travelled by the car before it gets side by side to the truck?

- 300 m
- 400 m
- 600 m
- 800 m

**Q.**A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p–1) sec and S2 be the displacement in the first p sec. The displacement in (p2–p+1)th sec will be

- S1+S2
- S1S2
- S1−S2
- S1S2

**Q.**The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s2. The distance covered by the body in the 5th second of its motion is

- 25 m
- 35 m
- 30 m
- 15 m

**Q.**A particle is moving in a straight line with initial velocity u and uniform acceleration f. If the sum of the distances travelled in tth and (t+1)th seconds is 100 cm, then its velocity after t seconds (in cm/s) is

- 20
- 30
- 50
- 80

**Q.**A body, moving in a straight line with an initial velocity of 5 ms−1 and a constant acceleration, covers a distance of 30 m in the 3rd second. How much distance will it cover in the next 2 seconds?

- 70 m
- 80 m
- 90 m
- 100 m

**Q.**A body A starts from rest with an acceleration a1 . After 3 seconds, another body B starts from rest with an acceleration a2 . If they travel equal distances in the 6th second after the start of A, then the ratio a1:a2 is equal to

- 5:9
- 3:5
- 5:11
- 5:7

**Q.**A body starts from rest and travels s m in 2nd second, then, acceleration is

- 3s2 m/s2
- 2s m/s2
- 2s3 m/s2
- 3s m/s2

**Q.**A particle having initial velocity 10 m/s is moving with constant acceleration 4 m/s2. The particle is moving in a straight line. Find the distance travelled by the particle in 7th second of its motion

- 10 m
- 5 m
- 28 m
- 36 m

**Q.**A body, moving in a straight line with an initial velocity of 5 ms−1 and a constant acceleration, covers a distance of 30 m in the 3rd second. How much distance will it cover in the next 2 seconds?

- 70 m
- 80 m
- 90 m
- 100 m

**Q.**The body started with velocity of 8 m/s and moving with an acceleration of 1 m/s2. The distance travelled by the body in 6th second is

- 17.5 m
- 13.5 m
- 10.0 m
- 18.5 m

**Q.**The initial velocity of a particle is 10 m/sec and its retardation is 2 m/sec2. The distance covered in the fifth second of the motion will be

- 1 m
- 9 m
- 5 m
- 7 m

**Q.**Assume that a car is able to stop with a retardation of 8 m/s2 and that a driver can react to an emergency in 0.5 sec. Calculate the overall stopping distance of the car for a speed of 72 km/hr of the car

- 25 m
- 10 m
- 35 m
- 30 m

**Q.**A body started with a velocity of 20 ms−1 and moving with an acceleration of 2 ms−2. The distance (in m) travelled by the body in the 8th second is

- 35
- 20
- 12
- 10

**Q.**A body A starts from rest with an acceleration a1 . After 2 seconds, another body B starts from rest with an acceleration a2 . If they travel equal distances in the 5th second after the start of A, then the ratio a1:a2 is equal to

- 5:9
- 5:7
- 9:5
- 9:7

**Q.**Figure (i) and (ii) below show the displacement time graphs of two particles moving along the x–axis. We can say that

- Both the particles are speeding up.
- Both the particles are speeding down.
- Particle (i) is speeding up while particle (ii) is speeding down.
- Particle (i) is speeding down while particle (ii) is speeding up.

**Q.**Two cars A and B are at rest and at the same point initially. If A starts with uniform velocity of 40 m/s and B starts in the same direction with constant acceleration of 4 m/s2 , then B will catch A after the time

- 10 s
- 20 s
- 30 s
- 35 s

**Q.**A body, moving in a straight line with an initial velocity of 5 ms−1 and a constant acceleration, covers a distance of 30 m in the 3rd second. How much distance will it cover in the next 2 seconds?

- 70 m
- 80 m
- 90 m
- 100 m

**Q.**Figure (i) and (ii) below show the displacement time graphs of two particles moving along the x–axis. We can say that

- Both the particles are speeding up.
- Both the particles are speeding down.
- Particle (i) is speeding up while particle (ii) is speeding down.
- Particle (i) is speeding down while particle (ii) is speeding up.

**Q.**A car is moving with initial velocity u=3 m/s and acceleration a=2 m/s2 then, the displacement of car in 6th second is

- 8 m
- 14 m
- 10 m
- 12 m

**Q.**List I gives some physical quantites, and List II gives some possible graphs

symbols have usual meaning i.e., a, v, x, t stands for acceleration, velocity, position and time. For given v - t graph correct match is? Where at t = 0, particle is at some positive position

- I→U, II→U, III→U, IV→Q
- I→P, II→Q, III→R, IV→Q
- I→U, II→P, III→R, IV→S
- I→U, II→U, III→U, IV→S

**Q.**A body starts from rest and travels s m in 2nd second, then, acceleration is

- 3s2 m/s2
- 2s m/s2
- 2s3 m/s2
- 3s m/s2

**Q.**A body starting from rest moving with uniform acceleration has a displacement of 16 m in first 4 s and 9 m in first 3 s. the acceleration of the body is

- 1 ms−2
- 2 ms−2
- 3 ms−2
- 4 ms−2

**Q.**The body started with velocity of 8 m/s and moving with an acceleration of 1 m/s2. The distance travelled by the body in 6th second is

- 17.5 m
- 13.5 m
- 10.0 m
- 18.5 m

**Q.**A body covers 26 and 28 meters in 10th and 11th seconds respectively. The body starts

- from rest and moves with uniform velocity.
- from rest and moves with uniform acceleration.
- with an initial velocity and moves with uniform acceleration.
- with an initial velocity and moves with uniform velocity.

**Q.**If body having initial velocity zero is moving with uniform acceleration of 8 m/sec2, the distance travelled by it in fifth second will be

- 36 m
- 40 m
- 30 m
- Zero

**Q.**As a car passes the point A on a straight road, its speed is 10 m/s. The car moves with constant acceleration a m/s2 along the road for T seconds until it reaches the point B, where its speed is v m/s. The car travels at this speed for a further 10 seconds, when it reaches the point C. From C it travels for a further T seconds with constant acceleration 3a m/s2 until it reaches a speed of 20 m/s at the point D. Choose the correct option(s).

[Given that the distance between A and D is 675 m]

- value of v is 12.5 m/s
- value of a is 18 m/s2
- value of T is 10 s
- value of T is 20 s

**Q.**Consider a particle initially moving with a velocity of 5 m/s starts decelerating at a constant rate of 2 m/s2. Find the distance travelled in the 2nd second.

- 1 m
- 5 m
- 2 m
- 8 m

**Q.**A body started with velocity of 20 ms−1 and moving with an acceleration of 2 ms−2. The distance travelled by the body in the 8th second is

- 35 m
- 20 m
- 45 m
- 30 m

**Q.**A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p–1) sec and S2 be the displacement in the first p sec. The displacement in (p2–p+1)th sec will be

- S1+S2
- S1S2
- S1−S2
- S1S2