EMF and EMF Devices
Trending Questions
Q.
What Is Discharge Rate Of Battery?
Q.
Assertion: In a simple battery circuit, the point of the lowest potential is the positive terminal of the battery.
Reason: The current flows towards the point of the higher potential, as it does in such a circuit from the negative to the positive terminal.
Both A and R are true and R is the correct explanation
A is true but R is false
Both A and R are false
Both A and R are true but R is not the correct explanation
Q. The example for non-ohmic resistance is
- Copper wire
- Carbon resistance
- Diode
- Tungsten wire
Q. Variation in the value of a current with time is shown in the figure below. The average value of the current in time t = 0 to t = T is
नीचे चित्र में समय के साथ धारा के मान में परिवर्तन दर्शाया गया है। समय t = 0 से t = T में धारा का औसत मान है
नीचे चित्र में समय के साथ धारा के मान में परिवर्तन दर्शाया गया है। समय t = 0 से t = T में धारा का औसत मान है
- i02
- i0
- i03
- i04
Q. A cylinder of radius R and length l is placed in a uniform electric field E parallel to the axis of the cylinder. The total flux over the curved surface of the cylinder is
- EπR2
- 2πR2E
- πR2E
- Zero
Q. In figure, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5 cm s−1. In this region, a magnetic field of 1 T exists. The electric current in the 9 Ω resistance is
- zero, if both wires slide towards left
- zero, if both wires slide in opposite directions
- 0.2 mA, if both wires move towards left
- 0.2 mA, if both wires moves in opposite directions
Q. Potential drop across 5 Ω is 10 V, then EMF of the battery is
- 12 V
- 28 V
- 30 V
- 40 V
Q. Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectivey. The voltage across the load lies between
- 11.7 V and 11.8 V
- 11.6 V and 11.7 V
- 11.5 V and 11.6 V
- 11.4 V and 11.5 V
Q. A potentiometer wire of length L and of resistance r is connected in series with a battery of e.m.f. E0 and a resistance r1. An unknown e.m.f. E is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by
- E0r(r+r1)×lL
- E0lL
- LE0r(r+r1)l
- LE0rlr1
Q. 10 identical cells are connected in series with similar polarity to an external resistance. Current through this resistance is ′I′. Now polarity of two cells are reversed, calculate current through same resistance.
- 0.2I
- 0.4I
- 0.6I
- 0.8I
Q. A charged particle (mass m and charge q) moves along x−axis with velocity v0. When it passes through the origin, it enters a region having uniform electric field E=−E^j which extends up to x=d. The equation of path of electron in the region x>d is :
- y=qEdmv20x
- y=qEd2mv20x
- y=qEdmv20(d2−x)
- y=qEdmv20(x−d)
Q. Each capacitor shown in the figure has a capacitance of 10 μF. The emf of the battery is 1 V. How much charge will flow through AB , if the switch S is closed?
- 103 μC
- 403 μC
- 203 μC
- 20 μC
Q. A potentiometer has a uniform potential gradient across it. Two cells connected in series - (i) to support each other and (ii) to oppose each other are balanced over 6 m and 2 m respectively on the potentiometer wire. The emfs of the cells are in the ratio
- 1 : 4
- 1 : 1
- 3 : 1
- 2 : 1
Q. EMF is a form of force.
- True
- False
Q. A magnetic field of B=5t2 exists in a cylindrical region as shown in figure. A conducting square loop of side l=2 cm is placed inside a cylinder such that one of the vertex of square is at the center of cylinder.
- EMF induced in side AB at t = 2 sec is 4 mV
- Potential difference developed in side OA at t = 2 sec is 2 mV
- Potential difference across side AB at t = 2 sec is 2 mV
- EMF induced across side OA at t = 2 sec is 2mV
Q. A parallel plate capacitor of capacitance C is connected to a battery and is charged to a voltage V. Another capacitor of capacitance 2C is similarly charged to a voltage 2V. The batteries are disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other capacitor. The final energy of the configuration is
- 25CV26
- 9CV22
- 3CV22
- 0
Q. In figure, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5 cm s−1. In this region, a magnetic field of 1 T exists. The electric current in the 9 Ω resistance is
- zero, if both wires slide towards left
- zero, if both wires slide in opposite directions
- 0.2 mA, if both wires move towards left
- 0.2 mA, if both wires moves in opposite directions
Q. Find the potential difference VP−VQ between points P and Q as shown below.
- 0 V
- 1 V
- −4 V
- 2 V
Q. is not an emf device.
- Electric Generator
- Battery
- Solar Cell
- Capacitor
Q. What is the internal mechanism in a cell that keeps its voltage constant?
- Chemical reaction
- Solar energy
- Heat
- Mechanical energy