Electric Field vs Magnetic Field
Trending Questions
Q. Maximum value of electric field at a point at a distance of 2 m from the light source of power 60 watt is
- 50N/C
- 30N/C
- 2×10−3N/C
- 5×10−3N/C
Q. A radio wave has a maximum magnetic field induction of 10−4T on arrival at a receiving antenna. The maximum electric field intensity of such a wave is
- zero
- 3× 104Vm−1
- 5.8 × 104T
- 3.0× 105T
Q. Which of the given relations is correct?
(c is speed of light, E is electric field strength and B is magnetic field strength)
(c is speed of light, E is electric field strength and B is magnetic field strength)
- c=2BE
- c=BE
- E=Bc
- B=cE
Q. A light beam travelling in the X-direction is described by the electric field Ey=(300 V/m)sin ω(t−x/c). An electron is constrained to move along the Y-direction with a speed of 2.0×107 m/s. Find the maximum electric force and the maximum magnetic force on the electron respectively.
- 4.8×10−17 N, 3.2×10−18 N
- 9.6×10−17 N, 6.4×10−18 N
- 2.4×10−17 N, 1.6×10−18 N
- 3.6×10−17 N, 2.5×10−18 N
Q. A laser beam has intensity I. What is the amplitude of electric field in the beam?
- √Iε0C
- √2 Iε0C
- √3 Iε0C
- √4 Iε0C
Q. A light beam travelling in the x-direction is described by the electric field Ey=300 Vm−1 sin ω(t−xc). An electron is constrained to move along the y-direction with a speed of 2.0×107 ms−1. Find the maximum electric force and the maximum magnetic force on the electron.
- FE=4.8×10−17N and FB=3.2×10−18N
- FE=8.4×10−18N and FB=3.2×10−18N
- FE=3.2×10−17N and FB=4.8×10−18N
- FE=4.8×10−17N and FB=6.4×10−17N
Q. Suppose that the electromagnetic wave in vacuum is
→E={(3.1NC)cos[(1.8radm)y+(5.4×106rads)t]^i
What is the frequency?
→E={(3.1NC)cos[(1.8radm)y+(5.4×106rads)t]^i
What is the frequency?
- 8.6×105Hz
- 4.3×105Hz
- 8.6×103Hz
- 4.3×103Hz
Q. An electromagnetic wave going through vacuum is described by E=E0sin(kx−ωt). Which of the following is/are independent of the wavelength?
- k
- ω
- k ω
- kω