Finding Average Velocity
Trending Questions
A car travels along a straight line for first half time with speed and the second half time with speed . Find the average speed of car.
On a 60km track, a train travels the first 30km with a speed of . How fast must the train travel the next 30km so as to average for the whole trip?
A car covers 20 km in 2 hours. Calculate the speed of the car?
An object moves the first half of the total distance with a speed of . If the average speed of the body is , the speed of the body when it traveled the remaining distance is ___________ .
3
6
4
- v1+v2+v33
- 3v1v2v3v1v2+v2v3+v3v1
- v1v2+v2v3+v3v13
- v1v2v33
A car covers a distance of 500 km with an average speed of 10 km h-1. How much time does it take to cover the distance?
A car is travelling in one hour. The distance travelled by the car in is _________.
- uvwuv+vw+uw
- 3uvwuv+vw+uw
- 2uvwuv+vw+uw
- 4uvwuv+vw+uw
Statement -2 : The average velocity of particle moving with constant acceleration in a time interval is →u+→v2 ,
where →u is the initial velocity and →v is the final velocity.
- Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1.
- Both statement 1 and statement 2 are correct but statement 2 is not the correct explanation of statement 1.
- Statement 1 is correct and statement 2 is incorrect.
- Statement 1 is incorrect and statement 2 is correct.
- (i) 20 (ii)5.55
- (i) 36 (ii) 10
- (i) 18 (ii) 5
- (i) 26 (ii) 7.2
- 4 m/s
- 5 m/s
- 3 m/s
- 6 m/s
- 2π ms−1
- 4π ms−1
- 2 ms−1
- 4 ms−1
If a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is
12√v1v2
v1+v22
2v1v2v1+v2
v1v23v1+2v2
- 20 and zero
- 0 and 20
- 20 and 20
- 6.3 and 20
- −10 m/s
- 12 m/s
- 10 m/s
- −8 m/s
- 3RT
- 6RT
- 2RT
- 4RT
- 2π3−√32
- 2π3−12
- π3−√32
- π3−12
- 2π ms−1
- 4π ms−1
- 2 ms−1
- 4 ms−1
A student walks to his school at a distance of 8 km with a constant speed of 2 km/h and walks back at a constant of 4 km/h. Calculate the average speed of the round trip.
- 145 m/s, 1 m/s
- 135 m/s, 1 m/s
- 135 m/s, 95 m/s
- 145 m/s, 95 m/s
- 22 m/s
- 25 m/s
- 27 m/s
- 29 m/s
- e4+1
- e4−1
- e4+4
- e4−4
- 506 m/s
- 5518 m/s
- 6118 m/s
- 436 m/s
Statement 2: If velocity is constant, then there is no change in the direction of motion.
- Statement-1 is True; Statement-2 is True; Statement -2 is a correct explanation for Statement-1.
- Statement-1 is True; Statement-2 is True; Statement -2 is NOT a correct explanation for Statement-1.
- Statement-1 is True; Statement-2 is False.
- Statement-1 is False; Statement-2 is True
- 1 km/min
- 2 km/min
- 3 km/min
- 4 km/min
- 145 m/s, 1 m/s
- 135 m/s, 1 m/s
- 135 m/s, 95 m/s
- 145 m/s, 95 m/s
- 5.5 m/s, 5 m/s
- 3.75 m/s, 3 m/s
- 3.5 m/s, 3 m/s
- 5.75 m/s, 5 m/s
- 8 ms−1
- 7.6 ms−1
- 6.4 ms−1
- 5.8 ms−1
- 94 m/s
- 88 m/s
- 104 m/s
- 90 m/s
- 5 m/s
- 4 m/s
- 4.6 m/s
- 3.6 m/s