Gravitational Potential Energy
Trending Questions
A satellite is revolving around the earth with a kinetic energy. The minimum addition of kinetic energy needed to make its escape from its orbit is
- 12.3 kW
- 7.0 kW
- 8.1 kW
- 10.2 kW
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 4√GML
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2√GML
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is √2GML
- the energy of the mass m remains constant
- −253 J
- −503 J
- 253 J
- Zero
- 12.3 kW
- 7.0 kW
- 8.1 kW
- 10.2 kW
A small body starts falling on to the earth from a distance equal to the radius of the earth's orbit. How long will the body take to reach the sun? Express the time in terms of T, period of revolution of the earth round the sun
T4√2
T2√2
T√2
T
An artificial satellite moving in a circular orbit around the earth has a total (kinetic + potential)energy Eo. Its potential energy is
−Eo
1.5 Eo
2 Eo
Eo
- mgR4
- 2mgR3
- 3mgR4
- mgR4
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 4√GML
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2√GML
- the minimum initial velocity of the mass m to escape the gravitational field of the two bodies is √2GML
- the energy of the mass m remains constant
- A shows the kinetic energy, B the total energy and C the potential energy of the system
- C shows the total energy, B the kinetic energy and A the potential energy of the system
- C and A are kinetic and potential energies respectively and B is the total energy of the system
- A and B are kinetic and potential energies and C is the total energy of the system
- 42×109 J
- 36×109 J
- 64×103 J
- 84×103 J
A body of mass m kg. starts falling from a point 2R above the earth’s surface. Its kinetic energy when it has fallen to a point ‘R’ above the eart’s surface [R – Radius of earth, M – Mass of earth, G – Gravitational constant]
12GMmR
16GMmR
23GMmR
13GMmR
The gravitational potential energy of a body of mass 'm' at the earth's surface −mgRe. Its gravitational potential energy at a height Re from the earth's surface will be (Here Re is the radius of the earth)
−2mgRe
2mgRe
12mgRe
−12mgRe
A mass M is split into two parts, m and (M-m), which are then separated by a certain distance. What ratio of mM maximizes the gravitational force between the two parts
13
12
14
15
- −253 J
- −503 J
- 253 J
- Zero
- mgh
- 67mgh
- 36mgh
- 56mgh