Inductive Reactance
Trending Questions
Q. When an L–R combination is connected in series with 12V – 50 Hz supply, a current of 0.5A flows through the combination. The current differs in phase from applied voltage by π3 rad. Then resistance is
- 24Ω
- 12Ω
- 6Ω
- 3Ω
Q. When a coil is connected to a D.C source of emf 12V, a current of 4 amp flows in it. If same coil is connected to 12V, 50Hz AC source, the current is 2.4A. The self inductance of the coil is
- 120π
- 110π
- 125π
- 15π
Q. Two inductors of self inductance L each and mutual inductance M are connected in series as shown in the figure.
Here ε0=100V, R=30Ω, L=2mH
ω=104 rad/s.
Here ε0=100V, R=30Ω, L=2mH
ω=104 rad/s.
- Maximum current in the circuit may be 3.33 A.
- Maximum current in circuit wil be 2A.
- Maximum current in the circuit may be less than 2A.
- Source voltage is ahead of current in circuit.
Q.
A coil has an inductance of 0.7H and is joined in series with a resistance of 220 Ω. When an alternating e.m.f. of 220V at 50 c.p.s. is applied to it, then the watt less component of the current in the circuit is
5 ampere
0.5 ampere
0.7 ampere
7 ampere
Q.
In the following circuit, the supply voltage is defined as: V(t) = 230 sin( 314t - π/6) and L = 2.2H. Determine the value of the current flowing through the coil.
1/3sin(314t - π /6)
1/3sin(314t - 2π/3)
3sin(314t - 2π/3)
1/3cos(314t - 5π/6)
Q. A resistance of 300Ω and an inductance of 1π henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is
- tan−143
- tan−134
- tan−132
- tan−125
Q. When an L–R combination is connected in series with 12V – 50 Hz supply, a current of 0.5A flows through the combination. The current differs in phase from applied voltage by π3 rad. Then resistance is
- 24Ω
- 12Ω
- 6Ω
- 3Ω
Q. An ideal inductor takes a current of 10 A when connected to a 125V, 50 Hz ac supply. A pure resistor across the same source takes 12.5 A. If the two are connected in series across a 100V, 40 Hz supply, the current through the circuit will be
- 7A
- 12.5A
- 20A
- 25A
Q. A resistance of 300Ω and an inductance of 1π henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is
- tan−143
- tan−134
- tan−132
- tan−125
Q. An ideal inductor takes a current of 10 A when connected to a 125V, 50 Hz ac supply. A pure resistor across the same source takes 12.5 A. If the two are connected in series across a 100V, 40 Hz supply, the current through the circuit will be
- 7A
- 12.5A
- 20A
- 25A