Instantaneous acceleration
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Q. A particle moves along a straight line. Its position at any instant is given by x=32t−8t33 where x is in m and t in s. The acceleration of the particle at the instant when particle is at rest will be
- −16 m/s2
- −32 m/s2
- 16 m/s2
- 32 m/s2
Q. A boy stretches a stone against the rubber tape of a catapult or 'gulel' (a device used to detach mangoes from the tree by boys in Indian villages) through a distance of 24 cm before leaving it. The tape returns to its initial normal position, accelerating the stone over the stretched length. The stone leaves the gulel with a speed of 2.2 m/s. Assuming that acceleration is constant while the stone was being pushed by the tape, find the magnitude.
- 8.1 m/s2
- 9.1 m/s2
- 10.1 m/s2
- 11.1 m/s2
Q. Given below are the equations of motion of four particles A, B, C and D.
xA=6t−3;
xB=4t2−2t+3;
xC=3t3−2t2+t−7;
xD=7cos60°−3sin30°
Which of these four particles move with uniform non-zero acceleration?
xA=6t−3;
xB=4t2−2t+3;
xC=3t3−2t2+t−7;
xD=7cos60°−3sin30°
Which of these four particles move with uniform non-zero acceleration?
- A
- B
- C
- D
Q.
The relation between time and distance is t=αx2+βx where α and β are constants. The retardation is
2αv3
2βv3
2αβv3
2β2v3
Q. The acceleration of a particle is increasing linearly with time t as bt . The particle starts from the origin with an initial velocity vo . The distance travelled by the particle in time t will be
- v0t+13bt2
- v0t+13bt3
- v0t+16bt3
- v0t+12bt2
Q. Velocity (V) versus displacement (S) graph of a particle moving in a straight line is as shown in the figure. Given Vo=4 m/s and So=20 m.
Corresponding acceleration (a) versus displacement (S) graph of the particle would be
Corresponding acceleration (a) versus displacement (S) graph of the particle would be
Q. A car accelerates uniformly from 13 ms–1 to 31 ms–1 while entering the motorway, covering a distance of 220 m. Then the acceleration of the car will be:
- 2.9 ms−2
- 1.8 ms−2
- 4 ms−2
- 2.2 ms−2
Q. The position of the particle is given by x=2t3−4t2+5 in m. The acceleration of the particle at 5 sec is
- 45 m/s2
- 48 m/s2
- 40 m/s2
- 52 m/s2
Q. Each of the four particles move along x axis. Their coordinate (in meters) as function of time (in seconds) are given by
Particle 1: x(t)=3.5−2.7t3
Particle 2: x(t)=3.5+2.7t3
Particle 3: x(t)=3.5+2.7t2
Particle 4: x(t)=3.5−3.4t−2.7t2
Which of these particles are speeding up for t>0?
Particle 1: x(t)=3.5−2.7t3
Particle 2: x(t)=3.5+2.7t3
Particle 3: x(t)=3.5+2.7t2
Particle 4: x(t)=3.5−3.4t−2.7t2
Which of these particles are speeding up for t>0?
- All four
- Only 1
- Only 2 and 3
- Only 2, 3 and 4
Q. A particle is moving along positive x-axis and at t=0, the particle is at x=0. The acceleration of the particle is a function of time. The acceleration at any time t is given by a=2(1–[t]) where [t] is the greatest integer function . Assuming that the particle is at rest initially, the average speed of the particle for the interval t=0 s to t=4 s is
- 1 m/s
- 0.5 m/s
- 2 m/s
- 1.5 m/s
Q. A particle moves along x-axis and its acceleration at any time t is a=2sin(πt), where t is in seconds and a is in m/s2. The initial velocity of particle (at time t=0) is u=0. The distance travelled (in meters) by the particle from time t=0 to t=1 s will be
- 2π
- 1π
- 4π
- None of these
Q. The velocity (V) versus displacement (S) graph of a particle moving in a straight line is as shown in the figure. Given Vo=4 m/s and So=20 m. At what displacement do velocity and acceleration have the same magnitudes?
- At S=5 m
- At S=10 m
- At S=30 m
- None of these
Q. Velocity (V) versus displacement (S) graph of a particle moving in a straight line is as shown in the figure. Given Vo=4 m/s and So=20 m.
Corresponding acceleration (a) versus displacement (S) graph of the particle would be
Corresponding acceleration (a) versus displacement (S) graph of the particle would be
Q. A particle moves along X− axis. It's equation of motion is x=2t(t−2) where t is in seconds. Choose the correct statement(s).
- The particle moves with a non-uniform acceleration.
- The particle momentarily comes to rest at t=1 sec.
- The particle performs SHM
- The given equation represents uniformly accelerated motion for t>1 sec
Q. Velocity of a car as a function of time is given by v(t)=(4t3−et+sint) in m/s. The acceleration in ( m/s2) of the car as a function of time t is
- 12t2−et−cost
- t2−et+cost
- 12t2−et+cost
- t2+et+cost
Q. The displacement x of a particle depends on time t as x=αt2−βt3. Then,
- The particle will return to its starting point after time αβ
- The particle will come to rest after time 2α3β
- The initial velocity of the particle was zero but its initial acceleration was not zero
- No net force will act on the particle at t=α3β
Q. Motion described by two different objects are shown in the figure. The ratio of accleration of the objects i.e. aAaB is
- 3:2
- 5:3
- 2:3
- 3:5
Q. A Porsche undergoing uniformly accelerated motion can go from 0 km/h to 100 km/h in 10 s. What is its instantaneous acceleration?
- 2.77 m/s2
- 3.66 m/s2
- −3.66 m/s2
- 0 m/s2