Intro to Collision
Trending Questions
Q.
A ball of mass m falls vertically to the ground from a height h1 and rebound to a height h2. The change in momentum of the ball on striking the ground is
mg(h1−h2)
m(√2gh1+√2gh2)
m√2g(h1+h2)
m√2g(h1+h2)
Q. A particle of mass 1 kg is initially at rest. A force starts acting on it in one direction whose magnitude changes with time. The (F - t) graph is shown in figure. The velocity of the particle at the end of 10 s is
- 150 m/s
- 120 m/s
- 100 m/s
- 112.5 m/s
Q. In an elastic collision in the absence of external forces, which of the following is correct?
- The linear momentum changes in collision
- The final kinetic energy is less than the initial kinetic energy
- The linear momentum is conserved
- The final kinetic energy is more than the initial kinetic energy
Q. Two balls of masses 2 kg and 4 kg are moving towards each other with speeds 6 m/s and 4 m/s respectively, on a frictionless surface. If the coefficient of restitution is 0.5, the relative velocity of seperation between the two balls is
- 1 m/s
- 2 m/s
- 5 m/s
- −1 m/s
Q. Two point masses connected by an ideal string are placed on a smooth horizontal surfaces as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass just after application of impulse will be 1x m/s, then value of x is
Q. Force-time(F - t) graph of a rocket of mass 1000 kg shown below describes the force on the rocket. Neglecting gravity, the velocity of rocket 16 s after starting from rest is
- 100 m/s
- 150 m/s
- 200 m/s
- 250 m/s
Q. Two point masses connected by an ideal string are placed on a smooth horizontal surfaces as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass just after application of impulse will be 1x m/s, then value of x is
Q. Two objects that are moving in the xy plane on a frictionless floor collide head on. Assume that they form a closed isolated system. The following table gives the momentum components in kg m/s before and after the collision. What are the missing values (a, b) (in kg m/s)?
Before collision along X-axisBefore collision along Y-axisAfter collision along X-axisAfter collision along Y-axisObjectPxiPyiPxfPyfA−453aBb−242
Before collision along X-axisBefore collision along Y-axisAfter collision along X-axisAfter collision along Y-axisObjectPxiPyiPxfPyfA−453aBb−242
- 11, 1
- 10, 11
- 5, 7
- 1, 11
Q. A ball is moving with a velocity of 8 m/s towards a surface which is also moving in a downward direction with velocity of 2 m/s as shown in figure. After collision with the surface, ball rebounds back. If the coefficient of restitution is e=0.5, find the rebound velocity of the ball. (Given:Velocity of surface will be same even after collision and all other external forces are absent.)
- 5 m/s
- 1 m/s
- 1.5 m/s
- 0.5 m/s
Q. The force F acting on a particle of mass m is indicated by the force - time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s is
- 24 N s
- 12 N s
- 20 N s
- 6 N s