# Introduction to acceleration

## Trending Questions

**Q.**

A body is moving with a velocity of $10m/s$. If the motion is uniform, what will be the velocity after **10** seconds?

**Q.**

Can an object be accelerated without speeding up or slowing down?

**Q.**The acceleration will be positive in which of the following graphs?

- (I) and (III)
- (I) and (IV)
- (II) and (IV)
- None of these

**Q.**A sports car can accelerate uniformly to a speed of 162 km/h in 5 s. Its maximum braking retardation is 6 m/s2. The minimum time in which it can travel 1 km, starting from rest and ending at rest, in seconds is?

**Q.**A body starts from rest with acceleration 2 m/s2 till it attains the maximum velocity, then retards to rest with 3 m/s2. If total time taken is 10 seconds then maximum speed attained is

- 12 m/s
- 8 m/s
- 6 m/s
- 4 m/s

**Q.**The average velocity of a body moving with uniform acceleration travelling a distance 3.06 m is 0.34 m/s. If the change in velocity of the body is 0.18 m/s during this time, its uniform acceleration is

- 0.01 m/s2
- 0.02 m/s2
- 0.03 m/s2
- 0.04 m/s2

**Q.**The velocity of a body is dependent on its position as v=√x, where v and x are in SI units. Then its acceleration

- increases linearly
- decreases linearly
- remains constant
- first increases and then decreases

**Q.**Velocity versus displacement graph of a particle moving in a straight line is as shown in figure. The acceleration of the particle is:

- Increases linearly with x
- Constant
- Increases parabolically with x
- None

**Q.**A car accelerates uniformly from 13 m/s to 31 m/s while entering the motorway, covering a distance of 220 m. Then the acceleration of the car will be:

- 2.9 m/s2
- 1.8 m/s2
- 4 m/s2
- 2.2 m/s2

**Q.**The displacement of a body in 8 s, starting from rest, with an acceleration of 20 cm/s2 is

- 64 m
- 64 cm
- 640 cm
- 0.064 m

**Q.**A particle is moving along x-axis whose acceleration is given as a=3x–4, where x is the location of the particle. At t=0, the particle is at rest at x=4/3. The distance travelled by the particle in 5 seconds is

- Infinite
- ≈42 m
- Zero
- None of these

**Q.**A sports car can accelerate uniformly to a speed of 162 km/h in 5 s. Its maximum braking retardation is 6 m/s2. The minimum time in which it can travel 1 km, starting from rest and ending at rest, in seconds is?

**Q.**For uniformly accelerated motion, both magnitude and

- strength
- direction
- speed

**Q.**The displacement (x) of a particle along a straight line at time t is given by x=a0+a12t+a23t2, the acceleration of the particle is

- a1/2
- a2/3
- a0+a2/3
- 2a2/3

**Q.**A body starts from orgin and moves along x-axis such that its velocity is v=(4t3−2t) m/s. Acceleration of particle when it is 2 m from origin is.

- 10 m/s2
- 20 m/s2
- 11 m/s2
- 22 m/s2

**Q.**

Column I | Column II | ||

(A) | →a⊥→v, a≠0 | (P) | Speed is constant |

(B) | →a∥→v, a≠0 | (Q) | Velocity is constant |

(C) | →a=0 | (R) | Speed is variable |

(D) | a≠0, →a neither parallel to →v nor ⊥→v | (S) | Motion is along a line |

Which of the following options has the correct combination considering column-I and column-II ?

- B → R, S
- A → Q
- D → S
- C → P, Q

**Q.**The position of the particle is given by x(t)=(4t2−3t+2t3), its acceleration will be

- 4t+2t2
- 12t2+8t
- 8t−3+6t2
- 12t+8

**Q.**A man loses 20% of his velocity after running through 108 m. If the rate by which he is losing his velocity remains constant, what is the maximum distance he will cover?

- 218 m
- 300 m
- 324 m
- 192 m

**Q.**The adjoining figures gives the velocity-time graph. This shows that the body is

- Starting from rest and moving with uniform velocity
- Moving with uniform retardation
- Moving with varying acceleration
- Having same initial and final velocity

**Q.**A body starts from rest with acceleration 2 m/s2 till it attains the maximum velocity, then retards to rest with 3 m/s2. If total time taken is 10 seconds then maximum speed attained is

- 12 m/s
- 8 m/s
- 6 m/s
- 4 m/s

**Q.**A particle is moving along the positive x-axis and at t=0, the particle is at x=0. The acceleration of the particle is a function of time. The acceleration at any time t is given by a=2(1–[t]) where [t] is the greatest integer function. Assuming that the particle is at rest initially, the displacement of the particle in 4 s is

- 1 m
- 2 m
- 6 m
- 4 m

**Q.**

**Assertion:**A body can have an acceleration even if its velocity is zero at a given instant of time.

**Reason:**A body is momentarily at rest when it reverses its direction of motion.

- If both assertion and reason are true and the reason is correct explanation of the assertion
- If both assertion and reason are true, but reason is not correct explanation of the assertion
- The assertion is true, but the reason is false
- The assertion is false and reason is true

**Q.**

**Assertion**: A positive acceleration of a body can be associated with a ‘slowing down’ of the body.

**Reason**: Acceleration is a vector quantity.

- If both assertion and reason are true and the reason is the correct explanation of the assertion.
- If both assertion and reason are true but reason is not the correct explanation of the assertion.
- If assertion is true but reason is false.
- If the assertion and reason both are false.
- If assertion is false but reason is true.

**Q.**The acceleration-displacement graph of a partice moving in a straight line is shown in the figure. Initial velocity of the particle is zero. Find the velocity of the particle when displacement of the particle is 12 m.

- 3√2 m/s
- 2√5 m/s
- 4 m/s
- 4√3 m/s

**Q.**

**Assertion**: A positive acceleration of a body can be associated with a ‘slowing down’ of the body.

**Reason**: Acceleration is a vector quantity.

- If both assertion and reason are true and the reason is the correct explanation of the assertion.
- If both assertion and reason are true but reason is not the correct explanation of the assertion.
- If assertion is true but reason is false.
- If the assertion and reason both are false.
- If assertion is false but reason is true.

**Q.**The position x of a body as a function of time t is given by the equation:

x=2t3−6t2+12t+16

The acceleration of the body is zero at time t is equal to

- 1 s
- 2 s
- 3 s
- 0.5 s

**Q.**A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further will it penetrate before coming to rest assuming that it faces constant resistance to motion?

- 1.5 cm
- 1.0 cm
- 3.0 cm
- 2.0 cm

**Q.**The relation between time and distance is t=αx2+βx, where α and β are constants. The retardation is

- 2αv3
- 2βv3
- 2αβv3
- 2β2v3

**Q.**A ball crosses point p with speed 6 m/s and returns same point p with speed 8 m/s in 5 seconds. Assuming acceleration(a) is uniform, find the magnitude of a

- 85 m/s2
- 65 m/s2
- 55 m/s2
- 145 m/s2