Kirchhoff's Voltage Law
Trending Questions
Q. In the circuit shown, what is the potential difference VPQ between points P and Q?
- +3 V
- +2 V
- −2 V
- None
Q. Both capacitors are initially uncharged and then connected as shown and switch is closed. What is the potential difference across the 3 μF capacitor?
- 30 V
- 10 V
- 25 V
- None of these
Q. In the given circuit potential of junction P is :
- 4 V
- 0 V
- 3.2 V
- 2.8 V
Q. If 24 cells each of internal resistance I Ω are to be connected in series and parallel combination to get the maximum power output across a load of 10 Ω. If x represents the number of rows and y represents the number of cells in each row. Which of the following relation between x and y is correct?
- y−x=23
- y−x=10
- y−x=23
- y−x=5
Q. If deflection of galvanometer is zero, then value of E is
Q. When the switches are arranged so that the current through the battery is maximum, what is the voltage across points A and B?
- 4 V
- 0 V
- 1 V
- 2 V
Q.
For a given L - C - R circuit, list 1 - gives voltage across source inductor, capacitor & resistance, and list -2 gives their magnitudes.
List -1List -II(I)∈(p)480(II)VL(Q)400(III)VC(R)240(IV)VR(S)200(T)160(U)0
If current in the circuit at an instant is 6A, then correct match for potential difference at that instant. [Neglect negative sign if any]
For a given L - C - R circuit, list 1 - gives voltage across source inductor, capacitor & resistance, and list -2 gives their magnitudes.
List -1List -II(I)∈(p)480(II)VL(Q)400(III)VC(R)240(IV)VR(S)200(T)160(U)0
If current in the circuit at an instant is 6A, then correct match for potential difference at that instant. [Neglect negative sign if any]
- I→P II→S III→T IV→U
- I→P II→Q III→T IV→R
- I→Q II→S III→T IV→R
- I→S II→T III→R IV→U
Q.
For a given L - C - R circuit, list 1 - gives voltage across source inductor, capacitor & resistance, and list -2 gives their magnitudes.
List -1List -II(I)∈(p)480(II)VL(Q)400(III)VC(R)240(IV)VR(S)200(T)160(U)0
If current in the circuit at an instant is 6A, then correct match for potential difference at that instant. [Neglect negative sign if any]
For a given L - C - R circuit, list 1 - gives voltage across source inductor, capacitor & resistance, and list -2 gives their magnitudes.
List -1List -II(I)∈(p)480(II)VL(Q)400(III)VC(R)240(IV)VR(S)200(T)160(U)0
If current in the circuit at an instant is 6A, then correct match for potential difference at that instant. [Neglect negative sign if any]
- I→P II→S III→T IV→U
- I→P II→Q III→T IV→R
- I→Q II→S III→T IV→R
- I→S II→T III→R IV→U
Q. When the switches are arranged so that the current through the battery is maximum, what is the voltage across points A and B?
- 4 V
- 0 V
- 1 V
- 2 V
Q. You are given many resistors, capacitors and inductors. These are connected to a variable DC voltage source (the first two circuits) or an AC voltage source of 50 Hz frequency (the next three circuits) in different ways as shown in Column II. When a current I (steady state for DC or rms for AC) flows through the circuit, the corresponding voltages V1 and V2 (indicated in circuits) are related as shown in Column I. Match the two columns.
Column I
Column II
i | I≠0, V1 is proportional to I | a | |
ii | I≠0, V2>V1 | b | |
iii | V1=0, V2=V | c | |
iv | I≠0, V2 is proportional to I | d | |
e |
- i - c, d, e ; ii - b, c, d, e ; iii - a, b ; iv - b, c, d, e
- i - c, d, e ; ii - b, c, e ; iii - a, b ; iv - b, c, d, e
- i - c, d ; ii - b, d, e ; iii - a, b ; iv - b, d, e
- i - c, e ; ii - b, c, d, e ; iii - a, b ; iv - b, c, e
Q. The incorrect option in the given circuit if the reading of ammeter is zero is
- The value of ε1 will be ε(R+r)R
- Current in R is ε1r+R
- Value of ε1 will be ε
- Potential across 2R is zero.
Q. A combination of secondary cells has an equivalent EMF of 2 V, internal resistance of 400 Ω. Maximum current that can be drawn is .
- 0.005 A
- 0.0005 A
- 0.010 A
- 0.010 A
Q. In a circuit, a metal filament lamp is connected in series with a capacitor of capacitance C μF across a 200 V, 50 Hz supply. The power consumed by the lamp is 500 W while the voltage drop across it is 100 V. Assume that there is no inductive load in the circuit. Take rms values of the voltages. The magnitude of the phase-angle (in degrees) between the current and the supply voltage is ϕ.
Assume, π√3≈5.
The value of C is -
Assume, π√3≈5.
The value of C is -