Magnetic Dip

Q.

What is the angle of dip at a place where the horizontal component of the earths magnetic field is equal to the vertical component?

Q.

At a certain place, the angle of dip is 60° and the horizontal component of the Earth’s magnetic field is 0.2 × 10^-4 T. Calculate the vertical component (in T) of the Earth’s magnetic field? (tan 60° = $\sqrt{3}$ )

1. $2\sqrt{3}\times {10}^{-4}$

2. $2\sqrt{3}$

3. $2\sqrt{3}\times {10}^{-5}$

4. $\frac{\sqrt{3}}{2}\times {10}^{-3}$

Q. At a certain place, the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is

1. ${60}^{\circ }$
2. ${45}^{\circ }$
3. ${90}^{\circ }$
4. ${30}^{\circ }$