Magnetic Field Due to a Circular Ring on the Axis
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Q. A disc of radius R uniformly charged with a charge Q is rotated at angular velocity ′ω′ about an axis passing through its center and perpendicular to plane disc. Net magnetic field at center of disc is.
- μ0uQωR
- μ0Qω4πR
- μ0Qω2πR
- μ0Qω2R
Q. A and B are concentric circular conductors with center O and carrying currents I1 and I2 as shown in fig. The ratio of their radii is 1: 2 and ratio of their flux densities at O is 1:3 The value of I1I2 is
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Q. A conductor of length l has shape of a semicylinder of radius R(<<l). Crossection of the conductor is shown in figure. Thickness of conductor is t(<<R) and conductivity of its material is δ=δ0cos θ. If an ideal battery of emf V is connected across its end faces, then magnetic field at point O on the axis of semicylinder is nμ0δ0Vtl. Here, n is
Q. A and B are concentric circular conductors with center O and carrying currents I1 and I2 as shown in fig. The ratio of their radii is 1: 2 and ratio of their flux densities at O is 1:3 The value of I1I2 is
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Q. Two identical thin rings, each of radius R, are coaxially placed a distance R apart . If Q1 and Q2 are respectively the charges uniformly spread on the two rings, the work done in moving a charge q from the centre of one ring to that of the other is equal to
- q(Q1−Q2)(√2+1)√2(4πε0R)
- q(Q1−Q2)(√2−1)√2(4πε0R)
- Zero
- q(Q1+Q2)(√2−1)√2(4πε0R)
Q.
A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be 18th to its value at the centre of the coil, is
R√3
R√3
2√3R
2√3R