Maxima & Minima in YDSE
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In Young's double slit experiment using two identical slits, the intensity of the maximum at the centre of the screen is I. What will be the intensity at the centre of the screen if one of the slits is closed?
I
I2
I4
None of these
Light of wavelengths λ is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is equal to the width of the slit if D equals
dλ
2λd
d22λ
2λ2d
- √n+1√n
- √n√n−1
- (√n+1√n−1)2
- (n+1n)2
Light of wavelengths λ is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is equal to the width of the slit if D equals
dλ
2λd
d22λ
2λ2d
- 1.25 cm, 1.5 cm
- 2.25 cm, 2.5 cm
- 3.25 cm, 3.5 cm
- 0.25 cm, 0.5 cm
In young's double slit experiment, the two slits act as coherent sources of equal amplitude A and of wavelength λ. In another experiment with the same set up, the two slits are sources of equal amplitude A and wavelength λ but are incoherent. The ratio of the intensity of light at the midpoint of the screen in the first case of that in the second case is
1:1
1:2
2:1
√2:1
- 4.0×10−7m
- 4.4×10−7m
- 6.6×10−7m
- 5.8×10−7m
- 416 nm only
- 624 nm only
- 416 nm and 624 nm only
- None of these
- 4.0×10−7m
- 4.4×10−7m
- 6.6×10−7m
- 5.8×10−7m
While light is used to illuminate the two slits in Young's double slit experiment. The separation between the slits is d and the distance between the screen and the slit is D (>> d). At a point on the screen directly in front of one of the slits, certain wavelengths are missing. The missing wavelengths are (here m=0, 1, 2, .....is an integer)
d2(2m+1)D
(2m+1)d2D
d2(m+1)D
(m+1)d2D
- 2 mm
- 1 mm
- 1.5 mm
- 1.1 mm