Net Acceleration for Non Uniform Circular Motion
Trending Questions
What work is done by a body moving along a circular path? Explain.
A body is whirling a stone tied with a string in a horizontal circular path. The string breaks, the stone:
will continue to move in the circular path
will move along a straight line towards the centre of the circular path.
will move along a straight line tangential to the circular path.
will move along a straight line perpendicular to the circular path away from the boy.
- aR
- a2R
- R√a4+b2
- none of these
- 0.15 m/s2
- 0.18 m/s2
- 0.2 m/s2
- 0.1 m/s2
Diagram shows the direction of the total acceleration and velocity of a particle moving clockwise in a circle of radius 5/√3 m at an instant of time. Tangential acceleration at this instant is 5 m/s2. Which of the following statements is not correct?
The centripetal acceleration is 5√3m/s2
Particle is speeding up
The net acceleration is 10 m/s2
The particle is slowing down
The coefficient of friction between the tyres and the road is 0.25. The maximum speed with which a car can be driven round a curve of radius 40 m without skidding is (assume g=10ms−2)
40 ms−1
20 ms−1
15 ms−1
10 ms−1
- √1616 m/s2
- √3240 m/s2
- √3814 m/s2
- √4160 m/s2
A motor cycle driver doubles its velocity when he is having a turn. The force exerted outwardly will be
Double
Half
4 times
14times
A road is 10 m wide. Its radius of curvature is 50 m. The outer edge is above the lower edge by a distance of 1.5 m. This road is most suited for the velocity
2.5 m/sec
4.5 m/sec
6.5 m/sec
8.5 m/sec
- tan−1(2π)
- tan−1(π)
- tan−1(3π)
- tan−1(2)
Diagram shows the direction of the total acceleration and velocity of a particle moving clockwise in a circle of radius 5/√3 m at an instant of time. Tangential acceleration at this instant is 5 m/s2. Which of the following statements is not correct?
The centripetal acceleration is 5√3m/s2
Particle is speeding up
The net acceleration is 10 m/s2
The particle is slowing down
- 0
- 12.5 ms−2
- 25 ms−2
- None of these
- 20×108 m/sec2
- 8×105 m/sec2
- 120×105 m/sec2
- 4×108 m/sec2
- 4 s
- 4/3 s
- 22/3 s
- √2 s
- 4.7 m/s2
- 3.8 m/s2
- 3 m/s2
- 2.7 m/s2
- 4.7 m/s2
- 3.8 m/s2
- 3 m/s2
- 2.7 m/s2
- 1rads
- √10 rads
- 2 rads
- 2√10 rads
- 0.15 m/s2
- 0.18 m/s2
- 0.2 m/s2
- 0.1 m/s2
- 2√5 m/s
- 3√5 m/s
- 5√2 m/s
- 5√3 m/s
A point P moves in counter-clockwise direction on a circular path as shown in the figure. The movement of 'P' is such that it sweeps out a length s=t3+5, where s is in meters and t is in seconds. The radius of the path is 20 m. The acceleration of 'P' when t = 2 s is nearly
13 m/s2
12 m/s2
7.2 m/s2
14 m/s2
- 0.86 ms−2, 54∘
- 0.68 ms−2, 45∘
- 1.0 ms−2, 45∘
- 0.5 ms−2, 45∘
- 2√5 m/s
- 3√5 m/s
- 5√2 m/s
- 5√3 m/s
An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m. The acceleration of a point on the tip of the blade is about
1600 m/sec2
4740 m/sec2
2370 m/sec2
5055 m/sec2
- ar=0, at=0
- ar=0, at≠0
- ar≠0, at=0
- None of these
- √1616 m/s2
- √3240 m/s2
- √3814 m/s2
- √4160 m/s2
Table-1 | Table-2 |
(A) Magnitude of tangential acceleration of particle | (P) decreases with time |
(B) Magnitude of centripetal acceleration of particle | (Q) increases with time |
(C) Magnitude of angular speed of particle with respect to centre of circle | (R) remains constant |
(D) Angle between the total acceleration and centripetal acceleration of particle | (S) depends on the value of radius |
- (A) - Q; (B) - Q; (C) - Q; (D) - P, S
- (A) - Q; (B) - Q, S; (C) - Q, S; (D) - P, S
- (A) - Q; (B) - Q, S; (C) - Q, S; (D) - P
- (A) - Q; (B) - P, S; (C) - P, S; (D) - Q, S