Net Contact Force
Trending Questions
A force of acts on a body of mass of . As a result, the body covers in moving along a straight line. Find the initial velocity.
A block of mass rests on a horizontal surface. If a horizontal force of is applied on the block, the frictional force on it is ( take, , )
- The contact force between block and the inclined plane is parallel to the incline.
- The contact force between block and the inclined plane is of magnitude m(g+a)
- The contact force between block and the inclined plane is perpendicular to the incline
- The contact force between block and the inclined plane is of magnitude mgcosθ
- Zero
- 50√17 N
- 100√5 N
- 200 N
- 30 N
- 40 N
- 50 N
- 100 N
A body of mass M is kept on a rough horizontal surface (friction coefficient = μ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on the body is F, where
F = Mg
F = μMg
Mg ≤ F ≤ Mg √1+μ2
Mg ≥ F ≥ Mg √1+μ2
- 30 N
- 40 N
- 50 N
- 100 N
- 30 N
- 40 N
- 50 N
- 100 N
- Zero
- 10 N
- 10√5 N
- 20 N
- 600 N throughout the journey.
- less than 600 N throughout the journey.
- more than 600 N throughout the journey.
- >600 N for a times Δt1 and Δt3 and =600 N for Δt2
- 9.8 N
- 0.7×9.8×√3 N
- 9.8×√3 N
- 0.7×9.8 N
- 600 N throughout the journey.
- less than 600 N throughout the journey.
- more than 600 N throughout the journey.
- >600 N for a times Δt1 and Δt3 and =600 N for Δt2
- t=4.2 s
- t=3.6s
- t=12.8 s
- Block will not return
A body of mass 400g slides on a rough horizontal surface. If the frictional force is 3.0 N, find (a) the angle made by the contact force on the body with the vertical and (b) the magnitude of the contact force. Take g = 10ms2
37∘, 5N
37∘, 4N
53∘, 4N
53∘, 5N