Net Force
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Q. Five forces −→F1, −→F2, −→F3, −→F4 and −→F5 are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s2 in east direction. If −→F1 force is removed then the acceleration becomes 7 m/s2 in north. Find the magnitude of acceleration of the block if only −→F1 is acting.
- 16 m/s2
- √65 m/s2
- √260 m/s2
- √33 m/s2
Q. When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the magnitude of acceleration of the particle is
- F1m
- F2F3mF1
- (F2−F3)m
- F2m
Q. A body of mass 5 kg under the action of constant force →F=Fx^i+Fy^j has velocity at t=0 s as →u=(6^i−2^j) m/s and at t=10 s as →v=6^j m/s. The force F is
- (−3^i+4^j) N
- (−35^i+45^j)N
- (3^i−4^j) N
- (35^i−45^j)N
Q. Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10 gm, what is the magnitude and direction of the force on the 7th coin (counted from the bottom) due to all the coins above it? Take g=10 m/s2
- 0.3 N downwards
- 0.3 N upwards
- 0.7 N downwards
- 0.7 N upwards
Q. An object of mass M is kept on a rough table as seen from above. Forces are applied as shown. Find the direction (from the vertical) of static friction if the object does not move.
- 30∘
- 37∘
- 45∘
- 53∘
Q. Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10 gm, what is the magnitude and direction of the force on the 7th coin (counted from the bottom) due to all the coins above it? Take g=10 m/s2
- 0.3 N downwards
- 0.3 N upwards
- 0.7 N downwards
- 0.7 N upwards
Q. A 2 kg object is subjected to three forces that give it an acceleration →a=−(8^i)m/s2. If two of the three forces are →F1=(30^i+16^j)N and →F2=(−12^i+8^j)N, find the third force (in N).
- 34^i+24^j
- −34^i−24^j
- 18^i+24^j
- −18^i−24^j
Q. A constant force of F=m2g2 is applied on the block of mass m1 as shown in figure. The string and the pulley are light and the surface of the table is smooth. The acceleration of m1 is
- m2g2(m1+m2) towards right.
- m2g2(m1−m2) towards left.
- m2g2(m2−m1) towards right.
- m2g2(m2−m1) towards left.
Q. A block of mass 2 kg slides down an incline plane of inclination 30∘. The coefficient of friction between block and plane is 0.5. The contact force between block and incline plane is :
- 25 N
- 10√3 N
- 5√7 N
- 5√15 N
Q. Two blocks A and B of mass M and 2M respectively, are hanging from a ceiling by means of a massless spring and a light string as shown. If the string between the blocks is suddenly cut and the downward acceleration is taken positive, then what will be the acceleration of the block A and B?
- g, 2g
- 2g, g
- −2g, g
- 2g, −g
Q. Two blocks ‘A’ and ‘B’ of same mass 'm' connected by a light spring are suspended by a string as shown in figure. Find the acceleration of block ‘A’ and ‘B’ just after the string is cut.
- 0, 2g
- 0, 0
- g, g
- 2g, 0
Q. A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel. The lift starts moving upwards with an acceleration 1.0 m/s2. If g=10 m/s2, the tension in the supporting cable is
- 9680 N
- 11000 N
- 1200 N
- 8600 N
Q. In the figure, all surfaces are smooth. Find the acceleration of the body and the force exerted by the floor on the body. (Take g=10 m/s2)
- 0, 100 N
- 4 m/s2, 200 N
- 2 m/s2, 210 N
- 0, 220 N
Q. Mr. A, B and C are trying to put a heavy piston into a cylinder at a mechanical workshop in a railway yard. If they apply forces F1, F2 and F3 respectively on the ropes, then, what is the relation between the forces if piston decends vertically with uniform speed?
- √3F1=F2+2F3
- √2F1=F2+F3
- 2F2=√3F1−F32
- F3=2F1−√3F2
Q. Find the reading of the spring balance if it is assumed to be of negligible mass.
(Take g=10 m/s2)
(Take g=10 m/s2)
- 2 kg
- 2.4 kg
- 3 kg
- 2.5 kg
Q. In the figure below, if all the surfaces are assumed to be smooth and the force F=100 N. If the acceleration of block B of mass 20 kg is a and tension in string connecting block A of mass 20 kg is T then, just after force F is applied find the values of T and a.
- T=0, and a=5 m/s2
- T=100 N, and a=0
- T=200 N, and a=5 m/s2
- T=100 N, and a=5 m/s2
Q. A block of mass 2 kg slides down an incline plane of inclination 30∘. The coefficient of friction between block and plane is 0.5. The contact force between block and incline plane is :
- 25 N
- 10√3 N
- 5√7 N
- 5√15 N
Q. Find the acceleration ( in m/s2) of 2 kg block in the figures (A) and (B) shown at the instant when 1 kg block falls from 2 kg block (at t=0). (Systems are in equilibrium at t=0)
(Take g=10 m/s2)
(Take g=10 m/s2)
- 0, 0
- 0, 5
- 5, 5
- 5, 0
Q. A gun fires 20 bullets/sec each of mass 20 gm, with a muzzle velocity of 50 m/s. Find the force required to hold the gun in position.
- 20 N
- 50 N
- 8.67 N
- 42.22 N
Q. Position of a 10 kg block moving under influence of a force is given as s=6t3+5t2+10 (m), where t is in seconds. Find out the force acting after 10 sec.
- 5000 N
- 4000 N
- 3600 N
- 3700 N
Q. Five persons A, B, C, D and E are pulling a cart of mass 100 kg on a smooth surface and cart is moving with acceleration 3 m/s2 in east direction. When person A stops pulling, it moves with acceleration 1 m/s2 in the west direction. When person B stops pulling, it moves with acceleration 24 m/s2 in the north direction. The magnitude of acceleration of the cart when only A and B pull the cart keeping their directions same as the old directions, is
- 24 m/s2
- 3√71 m/s2
- 30 m/s2
- 25 m/s2
Q. When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the magnitude of acceleration of the particle is
- F1m
- F2F3mF1
- (F2−F3)m
- F2m
Q. Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string produces an acceleration of 2 m/s2 in the upward direction in both the blocks. If T and T′ be the tensions in the two parts of the string, then (take g=10 m/s2 )
- T=72 N and T′=48 N
- T=48 N and T′=72 N
- T=48 N and T′=24 N
- T=24 N and T′=48 N
Q. A block of mass m=15 kg is attached to a spring of stiffness K=100 N/m. The block descends a plane inclined at an angle α=30∘ with horizontal. Assuming there is no friction, determine the acceleration of the block when the spring has stretched by a length x=0.05 m. (Acceleration due to gravity is 10 m/s2)
Q. Why is the block at rest despite an external force because of the pushing guy?
- Oh God, Newton's Laws are wrong, what should I do?
- Friction force by the block on the guy
- Friction force by the guy on the block
- Friction force by the ground on the block
Q. A projectile of mass 0.5 kg is thrown with a velocity of 30 m/s at an angle of 60∘ with the horizontal. Find the net force acting on the body when in air. (Take g=9.8 m/s2)
- 9.8 N
- 4.9 N
- 14.4 N
- 10 N
Q. A body of mass 5 kg under the action of constant force →F=Fx^i+Fy^j has velocity at t=0 s as →u=(6^i−2^j) m/s and at t=10 s as →v=6^j m/s. The force F is
- (−3^i+4^j) N
- (−35^i+45^j)N
- (3^i−4^j) N
- (35^i−45^j)N