Perfectly Elastic Collision
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In head on elastic collision of two bodies of equal masses
The velocities are interchanged
The speeds are interchanged
The momenta are interchanged
The faster body slows down and the slower body speeds up
- equal to 0
- less than 1
- equal to 1
- less than or equal to 1
As shown in figure, the block B of mass m starts from the rest at the top of a wedge W of mass M. All surfaces are without friction. W can slide on the ground, B slides down onto the ground, moves along it with a speed v, has an elastic collision with wall, and climbs back onto W. Then:
B will reach the top of W again
From the beginning, till the collision with the wall, the center of mass of ′B plus W′ is stationary
After the collision, the center of mass of ′B plus W′ moves with a velocity 2mvm+M
When B reaches its highest position on W, the speed of W is 2mvm+M
In an elastic collision of two particles the following is conserved
Momentum of each particle
Speed of each particle
Kinetic energy of each particle
Total kinetic energy of both the particles
- 23
- 13
- 16
- √32
- 5 ms−1
- 10 ms−1
- 20 ms−1
- 40 ms−1
A ball A is falling vertically downwards with velocity v1. It strikes elastically with a wedge moving horizontally with velocity v2 as shown in figure. What must be the ratio so that the ball bounces back in vertically upwards direction relative to wedge?
√3
1√3
2
12
- –0.3 m/s and 0.5 m/s
- 0.3 m/s and 0.5 m/s
- −0.5 m/s and 0.3 m/s
- 0.5 m/s and −0.3 m/s
- 50√2 Ns
- 25√3 Ns
- 50√3 Ns
- 25 Ns
- The average elastic force acting on the ball is m(u+v)Δt
- The average elastic force acting on the ball is 2m(u+v)Δt
- The kinetic energy of the ball increases by 2mu(u+v)
- The kinetic energy of the ball remans the same after the collision.
Two perfectly elastic particles P and Q of equal mass travelling along the line joining them with velocities 15 m/sec and 10 m/sec. After collision, their velocities respectively (in m/sec) will be
0, 25
5, 20
10, 15
20, 5
- 20 m
- 40 m
- 10 m
- 80 m
Two blocks A and B having the same mass collide elastically with each other. the velocity of block A before the collision is 10 m/s. If block A comes to rest after collision, then what was the velocity of block B before the collision?
- 10 m/s
- 0 m/s
- 20 m/s
- 30 m/s
A smooth sphere of mass 'M' moving with velocity 'u' directly collides elastically with another sphere of mass 'm' at rest. After collision their final velocities are 'V' and 'v' respectively. The value of 'v' is
2uMm
2umM
2u1+mM
2u1+Mm
Example: The bob A of a pendulum released from 30∘ to the vertical hits another bob B of the same mass at rest on table as shown in figure. How high does the bob A rise after the collision? Neglect the size of the bob and assume the collision to be elastic.
L−L√32
L−L2
zero
L−L√23
- m(θ0+θ1θ0−θ1)
- m2(θ0−θ1θ0+θ1)
- m(θ0−θ1θ0+θ1)
- m2(θ0+θ1θ0−θ1)
The bob A of a pendulum released from a height h hits head-on another bob B of the same mass of an identical pendulum initially at rest. What is the result of this collision? Assume the collision to be elastic.
Bob A comes to rest at B and bob B moves to the left attaining a maximum height h.
Bobs A and B both move to the left, each attaining a maximum height h2.
Bob B moves to the left and bob A moves to the right, each attaining a maximum height h2.
Both bobs come to rest.
n small balls, each of mass m, impinge elastically each second on a surface with velocity u. The force experienced by the surface will be
mnu
2 mnu
4 mnu
12 mnu
- Total momentum of the system is 3 kg m/s
- Momentum of 5 kg mass after collision is 4 kg m/s
- Kinetic energy of the centre of mass of system is 0.75 J
- Kinetic energy of the centre of mass of system is 1.75 J
A particle of mass 'm' is moving with horizontal speed 6 m/sec as shown in figure. If m << M, then for one dimensional elastic collision, the speed of lighter particle after collision will be
2m/sec in original direction
2 m/sec opposite to the original direction
4 m/sec opposite to the original direction
4 m/sec in original direction
A heavy steel ball of mass greater than 1 kg moving with a speed of 2 m sec−1collides head on with a stationary ping-pong ball of mass less than 0.1 gm. The collision is elastic. After the collision the ping-pong ball moves approximately with speed
2m sec−1
4m sec−1
2×104m sec−1
2×103m sec−1
- 2m√2ghcosθ
- 2m√ghcosθ
- 2m√2ghsinθ
- 2m√2gh
- 110 kgm/s
- 90 kgm/s
- −100 kgm/s
- 50 kgm/s
- 50%
- 66.7%
- 88.9%
- 100%
(consider collision to be perfectly elastic)
- 60∘
- 45∘
- 15∘
- 30∘
- 10 m
- 9 m
- 11 m
- 12 m
- –0.3 m/s and 0.5 m/s
- 0.3 m/s and 0.5 m/s
- −0.5 m/s and 0.3 m/s
- 0.5 m/s and −0.3 m/s
[Neglect friction between particle and the wedge and take M=2m, v0=10 m/s, tanα=2, g=10 m/s2.]
- 5 m/s
- 0 m/s
- 20 m/s
- 10 m/s
- m(θ0+θ1θ0−θ1)
- m2(θ0−θ1θ0+θ1)
- m(θ0−θ1θ0+θ1)
- m2(θ0+θ1θ0−θ1)
- −5 m/s and +2 m/s
- 3 m/s for both
- 5 m/s and 1 m/s
- None of these