Phasors
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Q. Figure shows the circular motion of a particle. The radius of the circle, the time period T, sense of revolution and the initial position are indicated in the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is
- x(t)=B sin(2πt30)
- x(t)=B cos(πt15)
- x(t)=B sin(πt15+π2)
- x(t)=B cos(πt15+π2)
Q. A particle starts from point x=−√32A and move towards negative extreme as shown in the figure below. If the time period of oscillation is T, then:
- The equation of the SHM is x=Asin(2πTt+4π3).
- The time taken by the particle to go directly from its initial position to negative extreme is T12.
- The time taken by the particle to reach mean position is T3.
- The equation of the SHM is x=Asin(2πTt+π3).
Q. A SHM is represented by the equation x=10 sin(πt+π6) in SI units. Find the maximum velocity of particle executing SHM.
- 10π m/s
- 10πm/s
- 2π3m/s
- −10 π m/s
Q. Figure shows the circular motion of a particle. The radius of the circle, the time period T, sense of revolution and the initial position are indicated in the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is
- x(t)=B sin(2πt30)
- x(t)=B cos(πt15)
- x(t)=B sin(πt15+π2)
- x(t)=B cos(πt15+π2)
Q. The displacement-time(x−t) graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=43s is
- √332π2 cm/s2
- −π232 cm/s2
- π232 cm/s2
- −√332π2 cm/s2
Q. A particle executes linear SHM of amplitude A along x− axis. At t=0 the position of the particle is x=A2 and it moves along +x direction. Find the phase constant (δ) if the equation is written as x=A sin(ωt+δ)
- 60∘
- 30∘
- 120∘
- 150∘
Q. A SHM is represented by the equation x=10 sin(πt+π6) in SI units. Find the maximum velocity of particle executing SHM.
- 10π m/s
- 10πm/s
- 2π3m/s
- −10 π m/s
Q. A particle starts from point x=−√32A and move towards negative extreme as shown in the figure below. If the time period of oscillation is T, then:
- The equation of the SHM is x=Asin(2πTt+4π3).
- The time taken by the particle to go directly from its initial position to negative extreme is T12.
- The time taken by the particle to reach mean position is T3.
- The equation of the SHM is x=Asin(2πTt+π3).
Q. A SHM is represented by the equation x=10 sin(πt+π6) in SI units. Find the maximum velocity of particle executing SHM.
- 10π m/s
- 10πm/s
- 2π3m/s
- −10 π m/s