Poisson's Effect
Trending Questions
Q. Which is correct relation. (σ is Poisson's Ratio, Y is the young's Modulus)
- Y <σ
- Y >σ
- Y=σ
- σ = +1
Q. A metal wire is stretched by a load. Then the fractional change in its volume ΔVV is proportional to
- ΔLL
- (ΔL2)2
- √ΔLL
- (ΔLL)3
Q. A steel wire of cross sectional area 0.05 cm2 is under a tension of 15 N. Find the decrease in the cross-sectional area. Young's modulus of steel = 2×1011N/m2 and Poisson's ratio = 0.3.
- 40×10−8cm2
- 50×10−8cm2
- 45×10−8cm2
- 22.5×10−8cm2
Q. Poisson's ratio is the ratio of lateral strain to the longitudinal strain.
- True
- False
Q. A compressive force is applied to a uniform rod of rectangular cross-section so that its length decreases by 1%. If the Poisson's ratio for the material of the rod is 0.2, then the volume approximately decreases by (in percentage).
Q. For the cube of given dimensions which is fixed at the bottom and acted upon by the force as shown in figure, identify the correct statement(s).
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
- Normal stress is 25√3 N/m2
- Shear stress is 25 N/m2
- Longitudinal strain is 12.5√3×10−11
- Magnitude of lateral strain is 10√3×10−11
Q. For the cube of given dimensions which is fixed at the bottom and acted upon by the force as shown in figure, identify the correct statement(s).
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
- Normal stress is 25√3 N/m2
- Shear stress is 25 N/m2
- Longitudinal strain is 12.5√3×10−11
- Magnitude of lateral strain is 10√3×10−11
Q. For the cube of given dimensions which is fixed at the bottom and acted upon by the force as shown in figure, identify the correct statement(s).
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
[Poisson's ratio =0.8 and Young's modulus =2×1011 N/m2]
- Normal stress is 25√3 N/m2
- Shear stress is 25 N/m2
- Longitudinal strain is 12.5√3×10−11
- Magnitude of lateral strain is 10√3×10−11