Position Time Graph
Trending Questions
When is the object at rest?
t = 5 sec
t = 10 sec
t = 20 sec
t = 30 sec
- The particle has come to rest 6 times.
- The maximum speed is at t=6 s.
- The velocity remains positive for t=0 to t=6 s.
- The average velocity for the total period shown is negative.
- 90 m
- 60 m
- 75 m
- 50 m
If the particle has a mass of 500 g, the force acting on the particle is (Assume x=t, y=t2 are equation of given graphs)
- 1 N along y− axis
- 1 N along x− axis
- 0.5 N along x− axis
- 0.5 N along y− axis
- vA>vB>vC
- vA>vC>vB
- vB>vA>vC
- vC>vA>vB
- False
- True
- ax=0 implies that at t=1 s, the angle between the particle’s velocity and the x axis is 45∘
- ax=0 implies ay=1 ms−2 at all times
- at t=0, the particle’s velocity points in the x−direction
- ax = 1 ms−2 implies that when the particle is at the origin, ay=1 ms−2
What is the distance of the body from the starting point at t = 30 s?
What is the distance of the body from the starting point at t = 30 s?
10 m
0 m
20 m
-10 m
- →vinst
- →v=0
- →vavg
The displacement-time graph for two particles A and B are straight lines inclined at angles of 30∘ and 60∘ with the time axis. The ratio of velocities of vA : vB is
1 : 2
1 : √3
√3 : 1
1 : 3
- y=x2
- y=1x2
- y=2x2
- y=1x
The displacement versus time curve is given below. Match the nearest option. (Assuming curves to be parabolic)
Column IColumn IIi.OAa. velocity increase with time linearlyii.ABb. velocity decreases with timeiii.BCc. velocity is independent of timeiv.CDd. velocity is zero
- i.→a., ii.→c., iii.→b., iv.→d.
- i.→a., ii.→c., iii.→d., iv.→b.
- i.→c., ii.→a., iii.→b., iv.→d.
- i.→a., ii.→b., iii.→c., iv.→d.
If the particle has a mass of 500 g, the force acting on the particle is (Assume x=t, y=t2 are equation of given graphs)
- 1 N along y− axis
- 1 N along x− axis
- 0.5 N along x− axis
- 0.5 N along y− axis
Its v−t graph will be:
What is the total distance travelled till 30 seconds?
-10 m
40 m
10 m
30 m