Position of a point
Trending Questions
Q. Instantaneous velocity of an object varies with time as v=α−βt2. Find its position, x as a function of time, t. Also find the object`s maximum positive displacement, xmax from the origin.
- x=αt−βt33 and xmax=23α3/2β3/2
- x=αt−βt33 and xmax=2αβ1/2
- x=2αt−β and xmax=2αβ
- x=2α2t−βt3 and xmax=2α1/2β3/2
Q. The position of point B with respect to point A is
- −13
- 13
- 6
- −7
Q. The figure shows the graph of the x−coordinate of a particle moving along the x−axis as a function of time. Average velocity during t=0 to t=6 s is
- 10 m/s
- 60 m/s
- 5 m/s
- 0
Q. A particle is moving along positive x− axis with velocity v=A−Bt, where A and B are positive constants and 't' is in seconds. If the particle is at the origin initially, then find the coordinates of the position of the particle at t=3AB.
- (0, 3A22B)
- (3A22B, 0)
- (0, −3A22B)
- (−3A22B, 0)
Q. A body of mass 2 kg moves under a force of (2^i+3^j+5^k) N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is .
(Round off to the Nearest Integer)
(Round off to the Nearest Integer)
Q. Initially the origin was at X=0 and position of a particle at point P was given as X=−3 m, if origin is shifted by 1 unit to the left, then position of point P with respect to new origin will be:
- 4 m
- −4 m
- −2 m
- −3 m
Q. The position of point B with respect to point A is
- −13
- 13
- 6
- −7
Q. At t=0, a particle starts from (4, 0) and moves towards positive x−axis with speed of v=8t+3 m/s. The final position of the particle as a function of time is
- 4t2−3t−4 m
- 4t2−3t+4 m
- 4t2+3t+4 m
- 4t2−3t m
Q. In the given figure, what is the position of point A from origin ?