Potential at a General Point Due to a Dipole
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Q. Two positive charges (+10 C) are kept on the arc of a circle and a negative charge (−20 C) at the origin (centre of circle). Find the magnitude of net dipole moment for the given system.
- 89.3 C-m
- 59.3 C-m
- 69.3 C-m
- 79.3 C-m
Q. Three charges are arranged on the vertices of an equilateral triangle as shown in figure. Find the magnitude of dipole moment of the combination.
- √2qd
- √3qd
- √5qd
- √6qd
Q. A positive point charge q is fixed at origin. A short dipole with a dipole moment p is placed along the x−axis far away from the origin with p pointing along the +x−axis. The kinetic energy of the dipole when it reaches distance d from origin is
- 3qp8πϵ0d2
- qp4πϵ0d2
- 2qp4πϵ0d2
- qp16πϵ0d2
Q. Two short electric dipoles are placed as shown in figure.
The energy of electric interaction between these dipoles will be :
[Take k=14πε0]
The energy of electric interaction between these dipoles will be :
[Take k=14πε0]
- −2kp1p2cosθr3
- −4kp1p2cosθr3
- 2kp1p2cosθr3
- −2kp1p2sinθr3
Q. Find the magnitude of electric field due to a dipole at a point P along the line joining point P and centre of dipole as shown in figure.
- 3.5×10−3 N/C
- 2.0×10−3 N/C
- 3.0×10−3 N/C
- 2.5×10−3 N/C
Q. Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p . If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle θ with the axis of the dipole, then the potential at P is given by (r >> 2a) (Where p = 2qa)
- V=pcos θ4πϵ0r2
- V=pcos θ4πϵ0r
- V=psin θ4πϵ0r
- V=pcos θ2πϵ0r2
Q. In the given situation the work done in moving a charge of 5C from point A to point B is .
- 10J
- 50J
- Zero
- None of these
Q. Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p . If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle θ with the axis of the dipole, then the potential at P is given by (r >> 2a) (Where p = 2qa)
- V=pcos θ4πϵ0r2
- V=pcos θ4πϵ0r
- V=psin θ4πϵ0r
- V=pcos θ2πϵ0r2