Potentiometer
Trending Questions
Q.
How is an ammeter connected in a circuit how is a voltmeter connected in a circuit?
Q. A battery of emf E0=12 V is connected across a 4 m long uniform wire having resistance 4 Ω/m. The cells of small emfs ε1=2 V and ε2=4 V having internal resistance 2 Ω and 6 Ω respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N, the distance of point N from the point A is equal to (in cm)
Q.
State whether a voltmeter has high resistance or low resistance. Give reason.
Q. A potentiometer wire 10 m long and having ‘20Ω′ resistance is connected in series with a battery and a resistance R=2160Ω. A Daniel cell of e.m.f 1.08 V is balanced across the P.D of the resistance ‘R’. The e.m.f of thermocouple is balanced across 300 cm of the wire. The e.m.f of thermocouple is
- 2 mV
- 4 mV
- 3 m/V
- 1 mV
Q. A cell is connected in the secondary circuit of a potentiometer and a balance point is obtained at 84 cm When the cell is shunted by a 5Ω resistor, the balance point changes to 70 cm. If the 5Ω resistor is replaced with 3Ω resistor then the balance point will be at
- 53 cm
- 63 cm
- 42 cm
- 112 cm
Q.
Where should a voltmeter be placed in a circuit?
Q. Potentiometer wire is 100 cm long and a constant potential difference is maintaned across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf's is:
- 5:1
- 5:4
- 3:4
- 3:2
Q. A daniel cell is balanced on 125 cm length of a potentiometer wire. When the cell is short circuited with a 2Ω resistance, the balancing length obtained is 100 cm. Internal resistance of the cell will be
- 1.5Ω
- 0.5Ω
- 1.25Ω
- 45Ω
Q. A 2 volt battery, a 15Ω resistor and a potentiometer of 100 cm length, all are connected in series. If the resistance of potentiometer wire is 5Ω, then the potential gradient of the potentiometer wire is
- 0.005 V/cm
- 0.05 V/cm
- 0.02 V/cm
- 0.2 V/cm
Q. In an experiment for calibration of voltmeter, a standard cell of emf 1.5V is balanced at 375cm length of potentiometer wire. The potential difference across a resistance in the circuit is balanced at 1.25 m. If a voltmeter is connected across the same resistance, it reads 0.6V. The error in the voltmeter is
- 0.1V
- 0.025V
- 0.235V
- 0.18V
Q. A potentiometer wire is 100 cm long and a constant p.d. is maintained across it. Two cells A and B are connected in series first and then in opposition. The balance points were obtained at 50 cm and 30 cm. Find the ratio of the e.m.f.s of the cells.
- 1:2
- 3:2
- 4:1
- 3:5
Q. Two cells of e.m.f. E1 and E2(E1>E2) are connected as shown in the figure. When a potentiometer is connected between A and B, the balancing length of the potentiometer wire is 300 cm. On connecting the same potentiometer between A and C, the balancing length is 100 cm. The ratio E1E2 is
- 3 : 1
- 1 : 3
- 2 : 3
- 3 : 2
Q. In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 5Ω resistance; and is at a length of 3 m when the cell is shunted by a 10Ω resistance. The internal resistance of the cell is, then
- 1.5Ω
- 10Ω
- 15Ω
- 1Ω
Q.
How is a voltmeter connected in a circuit?
Q. If a voltmeter draws zero current from the circuit then it is a potentiometer.
- False
- True
Q. AB is a potentiometer wire of length 100 cm and its resistance is 10 Ω. It is connected in series with a resistance R=40 Ω and a battery of emf 2 V and negligible internal resistance. If a source of unknown emf E is balanced by 40 cm length of the potentiometer wire, then the value of E is
- 0.8 V
- 1.6 V
- 0.08 V
- 0.16 V
Q. Three identical cells are connected across potentiometer as shown in figure. When switch S is open, null deflection length of potentiometer wire is 250 cm and when S is closed it is 200 cm. Then internal resistance of each cell is (up to two decimal places)
Q. The potentiometer works on the principle that at constant temperature, the resistance of a wire is proportional to its
- Length
- Area of cross section
- Material density
- None of the above
Q. A daniel cell is balanced on 125 cm length of a potentiometer wire. When the cell is short circuited with a 2Ω resistance, the balancing length obtained is 100 cm. Internal resistance of the cell will be
- 1.5Ω
- 0.5Ω
- 1.25Ω
- 45Ω
Q. In the following circuit the potential difference between the points B and C is balanced against 40 cm length of potentiometer wire. In order to balance the potential difference between the points C and D, where should jockey be pressed
- 32 cm
- 16 cm
- 8 cm
- 4 cm
Q. AB is a potentiometer wire of length 100 cm and its resistance is 10 Ω. It is connected in series with a resistance R=40 Ω and a battery of emf 2 V and negligible internal resistance. If a source of unknown emf E is balanced by 40 cm length of the potentiometer wire, then the value of E is
- 0.8 V
- 1.6 V
- 0.08 V
- 0.16 V
Q. A wire has a non-uniform cross-section as shown in figure. A steady current flows through it. The drift speed of electrons at point P and Q is vP and vQ.
- Data insufficient
- vP=vQ
- vP<vQ
- vP>vQ
Q. In the following figure, the p.d. between the points M and N is balanced at 50 cm. length. The length in cm, balancing for the potential difference between points N and C will be –
- 40
- 100
- 75
- 25
Q. A 2 volt battery, a 15Ω resistor and a potentiometer of 100 cm length, all are connected in series. If the resistance of potentiometer wire is 5Ω, then the potential gradient of the potentiometer wire is
- 0.005 V/cm
- 0.05 V/cm
- 0.02 V/cm
- 0.2 V/cm
Q. Potentiometer is an ideal voltmeter because:
- It has zero resistance
- It can measure infinite voltage.
- It can take infinite current from the circuit.
- It draws zero current from the circuit.
Q. A potentiometer has uniform potential gradient across it. Two cells connected in series (i) to support each other and (ii) to oppose each other are balanced over 6 m and 2 m respectively on the potentiometer wire. The emf’s of the cells are in the ratio of
- 1 : 2
- 1 : 1
- 3 : 1
- 2 : 1
Q. The resistivity of a potentiometer wire is 40×10−8Ωm and its area of cross section is 8×10−6 m2. If 0.2 ampere current is flowing through the wire, the potential gradient will be
- 10−2 volt/m
- 10−1 volt/m
- 3.2×10−2 volt/m
- 1 volt/m