Scalar and Vector Notation
Trending Questions
Q.
The resultant of two forces and is a force of . If the direction of force were reversed, the resultant would be . The value of is
Q. Two forces F1=(2^i–5^j−6^k) N and F2=(−^i+2^j−^k) N are acting on a body at the points (1, 1, 0) and (0, 1, 2) respectively. Find resultant torque acting on the body about point (−1, 0, 1) in (N-m).
- −10^i+14^j−9^k
- −14^i+5^j−9^k
- 14^i−9^j+10^k
- −14^i+10^j−9^k
Q. AB, CD, EG are perpendicular to each other. Select the correct statement(s) :
- Torque about the axis EG is 0
- Torque about the axis GH is 0
- Torque about the axis AB is (OG×F)
- Torque about the axis CD is (OG×F)
Q.
With two forces acting at a point, the maximum effect is obtained when their resultant is . If they act at right angles, then their resultant is . Then the forces are
Q. A rod of length 20 cm is kept along x axis. Two forces 5 N and 10 N are applied at distances 10 cm and 15 cm from point A as shown in figure. Find the point of application of net force from point A.
- 20 cm
- 12.5 cm
- 15 cm
- 17.5 cm
Q. The 20 cm diameter disc in the figure can rotate on the axle through its center. What is the net torque about O (in Nm)?
- 5.06
- 2.94
- 0.06
- 0.94
Q. Two forces −→F1=2^i−5^j−6^k and −→F2=−^i+2^j−^k are acting on a body at a point (1, 1, 0) and (0, 1, 2) respectively. Find the torque acting on the body about the point (−1, 0, 1).
- −14^i+10^j−9^k
- −11^i+10^j−12^k
- −3^i+3^k
- −14^i−10^j−9^k
Q. Two uniform rods of equal lengths but different masses are rigidly joined to form an L- shaped body, which is then pivoted about O as shown in the figure. Find the net torque about point O. Given M=m√3
- 0
- mgL(√34)
- mgl(2√3)
- mgL(√32)
Q.
How do you find the vector with the given magnitude of and in the same direction as ?
Q. A force →F=3^i+2^j−4^k acts at the point (1, −1, 2). Find its torque about the point (2, −1, 3).
- 6^i−7^j+^k
- 2^i−7^j−2^k
- 2^i+7^j−2^k
- 6^i+7^j+^k
Q. Two forces −→F1=2^i−5^j−6^k and −→F2=−^i+2^j−^k are acting on a body at a point (1, 1, 0) and (0, 1, 2) respectively. Find the torque acting on the body about the point (−1, 0, 1).
- −14^i+10^j−9^k
- −11^i+10^j−12^k
- −3^i+3^k
- −14^i−10^j−9^k
Q. Calculate the net torque on the system about the point O as shown in figure if F1=11 N, F2=9 N, F3=10 N, a=10 cm and b=20 cm (All the forces are along the tangents)
- 2.2 Nm out of the plane
- 3.0 Nm into the plane
- 2.2 Nm into the plane
- 3.0 Nm out of the plane
Q. A particle having mass m is projected with a speed v at an angle α with the horizontal ground. Find the torque of the weight of the particle about the point of projection when the particle reaches the ground.
- 2mv2sin2α
- mv2sin2α2
- mv2sin2α
- 0
Q. If →Fforce is acting on a particle having the position vector→r, and→τ be the torque of this force about the origin, then →τ.→F=0 and→r.→τ=0
- False
- True
Q. Angular momentum of a body is defined as the product of
- mass and angular velocity
- centripetal force and radius
- linear velocity and angular velocity
- moment of inertia and angular velocity