Screw Gauge

Q. A student measured the diameter of a small steel ball using a screw gauge of least count $0.001cm$. The main scale reading is $5mm$ and zero of circular scale division coincides with $25$ divisions above the reference level. If screw gauge has a zero error of $–0.004cm$, the correct diameter of the ball is

1. $0.521cm$
2. $0.053cm$
3. $0.529cm$
4. $0.525cm$

Q. A screw gauge has a negative error of 8 divisions. While measuring the diameter of a wire, the reading on the main scale is 3 divisions and the 24th circular scale division coincides with the base line. If the number of divisions on the main scale are 20 to a centimeter and the circular scale has 50 divisions, then the correct diameter of the wire is

1. 0.182 cm
2. 0.166 cm
3. 0.174 cm
4. 3.32 mm

Q. The pitch of a screw gauge is $2\text{mm}$ and there are $100$ divisions on the circular scale. In measuring the diameter of a sphere, there are $6$ divisions on the linear scale and $40$ divisions on circular scale coinciding with the reference line. The diameter of the sphere is:

1. $6.4\text{mm}$
2. $12.8\text{mm}$
3. $3.2\text{mm}$
4. $20\text{mm}$

Q. The distance between two consecutive threads of a Screw Guage is called

1. Least count
2. Pitch
3. Screw head
4. Nut head

Q. In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree $\left(0.5°\right)$ then the least count of the instrument is

1. one minute
2. half minute
3. half degree
4. one degree

Q. The pitch of a screw gauge is $2\text{mm}$ and there are $100$ divisions on the circular scale. In measuring the diameter of a sphere, there are $6$ divisions on the linear scale and $40$ divisions on circular scale coinciding with the reference line. The diameter of the sphere is:

1. $6.4\text{mm}$
2. $12.8\text{mm}$
3. $3.2\text{mm}$
4. $20\text{mm}$

Q. A screw gauge with a pitch of $0.5\text{mm}$ and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is $0.5\text{mm}$ and the 25th division coincides with the main scale line?

1. $0.50\text{mm}$
2. $0.75\text{mm}$
3. $0.80\text{mm}$
4. $0.70\text{mm}$

Q. A screw gauge having $100$ equal divisions and a pitch length of $1\text{mm}$ is used to measure the diameter of a wire of length $5.6\text{cm}$. The main scale reading is $1\text{mm}$ and ${47}^{\text{th}}$ circular division coincides with the main scale. The curved surface area of wire (in ${\text{cm}}^2$) to appropriate significant figures is

1. $1.60$
2. $3.20$
3. $1.25$
4. $2.6$

Q. In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree $\left(0.5°\right)$ then the least count of the instrument is

1. one minute
2. half minute
3. one degree
4. half degree

Q.

Find the least count of a screw gauge whose least count of linear scale is 1 mm and the circular scale is divided in 50 divisions and 2 entire rotations makes to 1 division on linear scale.

1. 0.1 mm

2. 0.01 mm

3. 0.02 mm

4. 0.2 mm

Q. The pitch of a screw gauge is $1\text{mm}$ and there are $100$ divisions on circular scale. When the faces $A$ and $B$ are just touching each without putting anything between the studs, the ${32}^{\text{nd}}$ division of the circular scale coincides with the reference line. The error in measurement due to screw gauge will be (zero of linear scale is not hidden from circular scale when $A$ and $B$ touches)

1. $-0.04\text{mm}$
2. $+0.32\text{mm}$
3. $+0.16\text{mm}$
4. $+0.04\text{mm}$