Surface Tension
Trending Questions
- Surface tension is more
- Surface tension is less
- Consumes less soap
- None of these
- become concave toward side A
- become concave toward side B
- become straight
- remain as it is
- increases
- remain constant
- decreases
- first decreases then increases
- 2TL
- 4TL
- 8TL
- 16TL
A container contains two immiscible liquids of density and . A capillary of radius is inserted in the liquid so that its bottom reaches up to denser liquid. Denser liquid rises in capillary and attains height equal to which is also equal to column length of lighter liquid. Assuming zero contact angle find the surface tension of the heavier liquid.
- becomes convex towards A.
- becomes concave towards A.
- remains in the initial position.
- either (a) or (b) depending on the size of A w.r.t. B.
- increases
- remain constant
- decreases
- first decreases then increases
- 0.0125 Nm−1
- 0.1 Nm−1
- 0.05 Nm−1
- 0.025 Nm−1
- is zero
- is infinity
- is same as that at any other temperature
- cannot be determined
- Due to surface tension, a liquid when spread over any surface tends to form spherical drops.
- It arises because of intermolecular forces, mainly due to cohesive forces.
- Surface tension increases, if temperature of liquid is increased keeping other parameters fixed.
- Surface tension is independent of the surface area of free surface of liquid.
Water is filled up to a height h in a beaker of radius R. The density of water is ρ, the surface tension of water is T and the atmospheric pressure is P0. Consider a vertical section ABCD of the water column through a diameter of the beaker. The force on water on one side of the section by water on the other side of this section has magnitude:
2P0Rh+πR2ρgh−2RT
2P0Rh+Rρgh2−2RT
P0πR2+Rρgh2−2RT
P0πR2+Rρgh2+2RT
- 200 dyne
- 750 dyne
- 800 dyne
- 600 dyne
- 0.06 N/m
- 0.08 N/m
- 0.05 N/m
- 0.09 N/m
A soap bubble of radius r is blown up to form a bubble of radius 2r under isothermal conditions. If σ is the surface tension of soap solution, the energy spent in doing so is
3πσr2
6πσr2
12πσr2
24πσr2
Water is kept in a beaker of radius 5.0 cm. Consider a diameter of the beaker on the surface of the water. Find the force by which the surface on one side of the diameter pulls the surface on the other side. Surface tension of water = 0.075 N m-1.
0.75 N
7.5 × 10-4 N
7.5 × 10-3 N
7.5 × 10-2 N
[Assume angle of contact between the wire and liquid is acute]
- σ=μg2cosθ
- σ=μg2sinθ
- If y<<a, then σ=μga2y
- If y<<a, then σ=μgay
- 0.1
- 0.2
- 0.001
- 0.002
- Acute
- Obtuse
- 90∘
- 0∘
- It gets doubled.
- It gets quadrupled.
- It remains the same.
- None of these.
- w1>w2>w3
- w1<w2<w3
- w1=w2=w3
- None of these
- 5×10−2N/m
- 3×10−2N/m
- 1.5×10−2N/m
- 1.2×10−2N/m
- N/m
- kg/cm
- dyne/cm
- dyne/m
- 0.1
- 0.2
- 0.001
- 0.002
- 3√2×10−2 N
- 32×10−2 N
- 32√2×10−2 N
- 3×10−2 N
[Take g=10 m/s2]
- 2 cm
- 4 cm
- 3 cm
- 1 cm
- 0.1
- 0.2
- 0.001
- 0.002
- 3√2×10−2 N
- 32×10−2 N
- 32√2×10−2 N
- 3×10−2 N
- Acute
- Obtuse
- 90∘
- 0∘
- density of liquid
- viscosity of air
- surface tension
- elasticity of liquid