Transmission of Wave
Trending Questions
What is path difference formula?
What is the difference between TE and TM mode?
If the speed of a wave doubles as it passes from shallow water into deeper water, its wavelength will be:
Unchanged
Doubled
Quadrupled
Halved
If the speed of a transverse wave on a stretched string of length is , what is the fundamental frequency of vibration?
A wave of frequency has a velocity of Calculate the distance between two points that are out of phase
- 33%
- 89%
- 67%
- 75%
- Point A represents node
- Point B represents antinode
- Point B represents node
- Both (a) and (b)
- Wave speed
- Amplitude
- Wavelength
- Frequency
- yt=32Aicos(k1x−ω1t)
- yt=23Aicos(k1x−ω1t)
- yt=32Aicos(2k1x−ω1t)
- yt=23Aicos(2k1x−ω1t)
- π
- 2π
- 0
- 3π
- Pi=Pt−Pr
- Pi=PiPr
- Pi=Pt×Pr
- Pi=Pt+Pr
- 12
- 2
- 14
- 4
- 0.01 mm
- 0.3 mm
- 0.02 mm
- 0.04 mm
- its frequency changes
- its wavelength does not change
- its speed does not change
- its amplitude may change
- 77 m/s
- 102 m/s
- 110 m/s
- 165 m/s
- 2:1
- 1:2
- 3:2
- 2:3
- 0.2 sin (π(3t+x))
- −0.2 sin (3πt+πx)
- 0.5 sin (πt+x)
- 0.2 sin(π(3t−x))
yi=(3 cm)cos[(3.14 cm−1)x−(314 rad s−1)t]. What is the expression for the transmitted waves?
- yt=(3 cm)cos[(3.14 cm−1)x−(314 rad s−1)t)]
- yt=(1.5 cm)cos[(3 cm−1)x−(9.42 rad s−1)t]
- yt=(3 cm)cos[(9.42 cm−1)x−(3.14 rad s−1)t]
- yt=(1.5 cm)cos[(9.42 cm−1)x−(314 rad s−1)t]
The harmonic wave yi = (2.0 × 10−3) cos π (2.0 x −50t) travels along a string toward a boundary at x = 0 with a second string. The wave speed on the second string is 50 m/s. What are the expressions for reflected and transmitted waves. Assume SI units
6.67 × 10−4 cos π (2.0x + 50t), 2.67 × 10−3 cos π (x − 50t)
6.67 × 10−4 cos π (2.0x − 50t), 2.67 × 10−3 cos π (x − 50t)
6.67 × 10−4 cos π(2.0x + 50t + π), 2.67 × 10−3 cos π (x − 50t)
6.67 × 10−4 cos π(2.0x − 50t + π), 2.67 × 10−3 cos π (x − 50t)
Find the time taken by the pulse in travelling through a distance of 50 cm on the string. Take g=10 m/s2
- 0.04 s
- 0.03 s
- 0.05 s
- 0.08s
The wavelength of waves produced on the surface of the water is 20 cm. If the wave velocity is 24 m/s calculate the number of waves produced in one second.
- λ2>λ1
- λ2=λ1
- λ2<λ1
- Cannot be predicted
[Assume, tension in both the strings is same]
- 2:3
- 3:2
- 5:9
- 9:5
[Assume tension to be same]
- 4
- 1
- 2
- 6
- Amplitude of the reflected wave is 43×10−3 m.
- Amplitude of the transmitted wave is 163×10−3 m.
- Amplitude of the reflected wave is 163×10−3 m.
- Amplitude of the transmitted wave is 43×10−3 m.