Work Done by Friction
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Statement I: A block of mass m starts moving on a rough horizontal surface with a velocity v. It stops due to friction between the block and the surface after moving a certain distance. The surface is now tilted to an angle of 30∘ with the horizontal, and the same block is made to go up on the surface with the same initial velocity v. The decrease in the mechanical energy in the second situation is smaller than that in the first situation.
Statement II: The coefficient of friction between the block and the surface decreases with the increase in the angle of inclination.
If statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
If statement I is true, Statement II is true; Statement II is not correct explanation for Statement I
If statement I is true, Statement II is false
If statement I is false, Statement II is true
- 0 J
- 5 J
- 10 J
- −5 J
A large slab of mass 5 kg lies on a smooth horizontal surface, with a block of mass 4 kg lying on top of it. The coefficient of friction between the block and the slab is 0.25. If the block is pulled horizontally by a force of F = 6 N, the work done by the force of friction on the slab, between the instants t=2 s and t=3 s, is (g = 10 ms−2)
2.4 J
5.55 J
4.44 J
10 J
- True
- False
- 12000 J
- 10000 J
- −6000 J
- 0 J (because friction is present)
- 0.231
- 0.501
- 0.110
- 0.23
- 8 J
- Zero
- 16 J
- 10 J
Calculate the work done by kinetic friction in 10 sec (g=9.8 m/s2)
- 246.96 J
- −246.96 J
- 882 J
- −882 J
- Zero
- Positive
- Negative
- cannot be determined
The work done by kinetic friction on an object is always negative.
True
False
- True
- False
- 3 mgh
- mgh
- mgh sin θ
- 2 mgh