Work Energy Theorem Application
Trending Questions
A particle of mass m moves with a variable velocity v, which changes with distance covered x along a straight line as v=k√x, where k is a positive constant . The work done by all the forces acting on the particle, during the first t second is
mk4t2
mk4t24
mk4t28
mk4t216
(Take g=10 m/s2)
- 72 s
- 32 s
- 12 s
- 52 s
- 750 J
- 7.5×103 J
- 4500 J
- 7.5×104 J
- 5
- 10
- 11
- 20
- 15500 J
- −15500 J
- −31000 J
- 31000 J
The same retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance will be
The same
Doubled
Halved
Four times
- 300 J
- 325 J
- 275 J
- 350 J
The work done in pulling up a block of wood weighing 2 kN for a length of 10m on a smooth plane inclined at an angle of 15∘ with the horizontal is
4.36 kJ
5.17 kJ
8.91 kJ
9.82 kJ
- 916
- 14
- 15
- 925
- h- htanα
- hμ - htanα
- hμ - h
- hμ - 1tanα
- √2gL and 3mg
- √gL and 3mg
- √2gL and 4mg
- √gL and 2mg
The only force acting on a 2.0 kg body as it moves along the x - axis varies as shown in the figure. The velocity of the body at x = 0 is 4.0 ms What is the maximum K.E attained by the body between x=0 and x=5 m?
12 J
18 J
20 J
16 J