A(0, 0), B(6, 0), C(4, 2), D(2, 2) are the vertices of trapezium ABCD.

E and F are the midpoints of AD and BC respectively then, EF =?.

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Solution

The correct option is B

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Similar questions

In a trapezium ABCD, E and F be the midpoints of the diagonals AC and BD respectively. Then, EF = ?

(a) $\frac{1}{2} A B$

(b) $\frac{1}{2} C D$

(d) $\frac{1}{2} (A B - C D)$

E

F

A D

B C

A B C D

E F

| | A B a n d E F = \frac{1}{2} (A B + C D)

E F | | A B a n d E F = \frac{1}{2} (A B + C D)

A D, B C

A B C D

E F | | A B

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