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Standard XII

Chemistry

Elevation in Boiling Point

A 0.001 molal...

Question

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

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Solution

The correct option is B

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Similar questions

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} c l_{4}]

in water had a freezing point depression of

{0.0054}^{\circ}

. If

K_{f}

for water is 1.80, the correct formulation for the above molecule is

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} C l_{4}]

in water has a freezing point depression of

{0.0054}^{0} C

. If

K_{f}

for water is 1.80 K.kg.mol

^{- 1}

, the correct formulation of the above molecule is:

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

0.001

molal solution of

[P t {({N H}_{3})}_{4} {C l}_{4}]

in water had a freezing point depression of

0.0054^{o} C

. If

K_{f}

for water is

1.80

, the correct formula of the compound is :

Q. A 0.001 molal solution of a complex represented as

[P t (N H_{3})_{4} C l_{4}]

in water had freezing point depression of

{0.0053}^{o} C

. Given,

K_{f}

for

H_{2} O = 1.86 K m o l a l i t y^{- 1}

. Assuming 100% ionisation of the complex, write the ionisation nature and formula of complex.

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A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If Kf for water is 1.80, the correct formulation for the above molecule is

The correct option is B

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is