You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Elevation in Boiling Point

A 0.001 molal...

Question

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

Suggest Corrections

Similar questions

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} c l_{4}]

in water had a freezing point depression of

{0.0054}^{\circ}

. If

K_{f}

for water is 1.80, the correct formulation for the above molecule is

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} C l_{4}]

in water has a freezing point depression of

{0.0054}^{0} C

. If

K_{f}

for water is 1.80 K.kg.mol

^{- 1}

, the correct formulation of the above molecule is:

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

0.001

molal solution of

[P t {({N H}_{3})}_{4} {C l}_{4}]

in water had a freezing point depression of

0.0054^{o} C

. If

K_{f}

for water is

1.80

, the correct formula of the compound is :

Q. A 0.001 molal solution of a complex represented as

[P t (N H_{3})_{4} C l_{4}]

in water had freezing point depression of

{0.0053}^{o} C

. Given,

K_{f}

for

H_{2} O = 1.86 K m o l a l i t y^{- 1}

. Assuming 100% ionisation of the complex, write the ionisation nature and formula of complex.

Join BYJU'S Learning Program

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If Kf for water is 1.80, the correct formulation for the above molecule is

The correct option is B

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is