A 0-001 molal solution of - Pt N H 34 cl 4- in water had a freezing point depression of 0-0054- - If K f for water is 1-80- the correct formulation for the above molecule isA- -PtN H34 C l4-B- -P tN H34 C l3- C lC- - Pt NH 34 Cl 2- Cl 2D- -P tN H34 C l2- C l3

The correct option is C [Pt(NH3)4Cl2]Cl2T=i K_f m ⇒ i= T_f/K_f m=0.0054/1.80×0.001=3 Thus complex produces three ions per molecule. hence possible correct for ...

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Byju's Answer

Standard XII

Chemistry

Depression in Freezing Point

A 0.001 molal...

Question

A 0.001 molal solution of $[P t (N H_{3})_{4} c l_{4}]$ in water had a freezing point depression of ${0.0054}^{\circ}$ . If $K_{f}$ for water is 1.80, the correct formulation for the above molecule is

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[Pt(NH₃)₄Cl₂]Cl₂

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Solution

The correct option is D [Pt(NH₃)₄Cl₂]Cl₂
$△ T = i K_{f} m$
$\Rightarrow i = \frac{△ T_{f}}{K_{f} m} = \frac{0.0054}{1.80 \times 0.001} = 3$
Thus complex produces three ions per molecule. hence possible correct formula is
$[P t (N H_{3})_{4} C l_{2}] C l_{2}$

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