A $0.001$ molal solution of $[P t (N H_{3})_{4} C l_{4}]$ in water had a freezing point depression of ${0.0054}^{o} C$ . If $K_{f}$ for water is 1.80, the correct formulation of the above molecule is:

[P t (N H_{3})_{4} C l_{3}] C l

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[P t (N H_{3})_{4} C l_{3}] C l_{2}

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[P t (N H_{3})_{4} C l] C l_{2}

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[P t (N H_{3})_{4} C l_{4}]

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Solution

The correct option is B $[P t (N H_{3})_{4} C l_{3}] C l_{2}$
$Δ T_{f} = i \times K_{f} \times m$
$0.0054 = i \times 1.80 \times 0.001$

The van't Hoff factor $i = 3$

This suggests that 1 molecule of $[P t (N H_{3})_{4} C l_{4}]$ dissociates in solution to produce 3 ions. Hence, the correct formula of the complex is $[P t (N H_{3})_{4} C l_{3}] C l_{2}$
$[P t (N H_{3})_{4} C l_{3}] C l_{2} \to [P t (N H_{3})_{4} C l_{3}]^{2 +} + 2 C l^{-}$

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Similar questions

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} C l_{4}]

in water has a freezing point depression of

{0.0054}^{0} C

. If

K_{f}

for water is 1.80 K.kg.mol

^{- 1}

, the correct formulation of the above molecule is:

A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is