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Molarity

A 0.01 D* sol...

Question

A 0.01 D* solution of KCl has a specific conductance value of
$0.00141 m h o c m^{- 1} .$ A cell filled with this solution has a resistance of 4.2156 ohms. What is the cell constant?

0.00594 c m^{- 1}

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0.01593 c m^{- 1}

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0.10592 c m^{- 1}

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0.06596 c m^{- 1}

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Solution

The correct option is A $0.00594 c m^{- 1}$
$Cell constant = \frac{specific conductance}{conductance}$
$= \frac{specific conductance}{1/resistance}$
$= \frac{0.00141}{1/4.2156} = 0.00594 c m^{- 1}$

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