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Question

A 0.1 M aqueous solution of a weak acid is 2% ionized. If the ionic product of water is 1×1014, the [OH] is:

A
5×1012M
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B
2×103M
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C
1×014M
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D
none of these
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Solution

The correct option is D 5×1012M
Degree of dissociation of weak acid, α=2100=0.02

Concentration of acid is [H+]=Cα=0.1×0.02=0.002

Ionic product of water =1×1014

[H+][OH]=1×1014

[OH]=1×10140.002=5×1012

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