A 0-1 M solution of HF is 1 - ionized- What is the K a -A- 10-5B- 10-4- 3 - 10-5D- 3 - 10-4

The correct option is A 10^ 5Ka =C ∝^2 =0.1 × (0.01) =10^ 5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equilibrium Constant and Standard Free Energy Change

A 0.1 M solut...

Question

A 0.1 M solution of HF is 1% ionized. What is the $K_{a}$ :-

10^{- 5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10^{- 4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 \times 10^{- 5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 \times 10^{- 4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

3.75 \times 10^{- 4} o h m^{- 1} c m^{- 1}

λ^{\infty}

250 o h m^{- 1} c m^{2} m o l^{- 1}

0.1 M

H C N

(K_{a} = 4 \times 10^{- 10})

0.1 M

H F

(K_{a} = 6.7 \times 10^{- 4})

h

0.1 M

298 K

K_{a} = 1.8 \times 10^{- 5}

0.10 M

K_{a}

p H

0.5 M

H F

(K_{a} = 2 \times 10^{- 3})

Join BYJU'S Learning Program