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Abnormal Colligative Properties

A 0.1 molal...

Question

A $0.1$ molal solution of a monobasic acid is $45 %$ ionized. Calculate the depression in freezing point:
(Molecular weight of the acid $= 300$ g/mol, $K_{f} = 1.86 K {m o l}^{- 1} k g$ )

- {0.199}^{o} C

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{2.00}^{o} C

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0^{o} C

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{0.269}^{o} C

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Solution

The correct option is D ${0.269}^{o} C$
If acid is $45$ % ionized then $α = 0.45$

$Δ T_{f} = m o l a l i t y \times K_{f} = 0.1 \times 1.86 = {0.186}^{0} C$

Now, for monobasic acid

$H A ⇋ H^{+} + A^{-}$

$Δ T_{e x p} = Δ T_{f} (1 + α) = 0.186 (1 + 0.45) = {0.269}^{o} C$

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