Question

A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: $x=\left(10cm\right)cos\left[\right(10rads)t+\frac{\pi }{2}rad]$ . What is the maximum acceleration experienced by the block

[AMU (Engg.) 2000]

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

a = 10 $\times {10}^{-2}mand\omega$ = 10 rad/sec

$A_{max}={\omega }^{2}a=10\times {10}^{-2}\times {10}^2=10m/se{c}^2$