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Question

A 0.2 molar solution of formic acid is 3.2% ionized, its ionization constant is:

A
9.6×103
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B
2.1×104
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C
1.25×106
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D
2.1×108
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Solution

The correct option is A 2.1×104
HCOOH+H2OH3O++COOH
C O O
CCα Cα Cα

We know
Ka=C2α2C(1α)

We are given C=0.2M

α=3.2%=0.032

Ka=0.2×(0.032)2(10.032)

Ka=2.1×104

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