CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 0.200kg mass is hung on a vertical spring which has spring constant k=5.6N/m, balanced such that the mass is motionless.
How much does the spring stretch relative to its original length as a result of the mass hanging on it?
Take the mass of the spring to be negligible.

A
0.04m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.11m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.35m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.70m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
0.84m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.35m
Given : m=0.200 kg k=5.6 N/m
The force exerted by the spring balances the weight of the hanging mass.
kx=mg
OR 5.6×x=0.200×9.8 x=0.35 m

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservative Forces and Potential Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon